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irina [24]
3 years ago
5

PLEASE HELP WITH THIS ILL GIVE BRAINLIEST

Mathematics
2 answers:
Mrrafil [7]3 years ago
5 0

Answer:

\text{a. }x=7, x=-7, \\\text{b. }x=16, x=-16,  \\\text{c. }x=3, x=-17, \\\text{d. }x=7, x=-7

Step-by-step explanation:

For |x|=y, we have two cases:

\begin{cases}x=y, \\x=-y\end{cases}

Using this, we can solve all four of the problems:

\text{a. }|x|=7,\\\begin{cases}x=7, \\x=-7\end{cases}

\text{b. }|2x|=32,\\\begin{cases}x=16, \\x=-16\end{cases}

\text{c. }|x+7|=10,\\\begin{cases}x+7=10, x=\boxed{3,} \\x+7=-10, x=\boxed{-17}\end{cases}

\text{d. }5|x|=35,\\\begin{cases}x=7, \\x=-7\end{cases}

Gala2k [10]3 years ago
3 0

Answer:

a) x = 7, x = - 7

b) x = 16, x = - 16

c) x = 3, x = - 17

d) x = 7, x = - 7

Step-by-step explanation:

When you have absolute value on a variable, the variable has two results.

Example:

lxl = 2

x = 2, or x = - 2

a. lxl = 7

x = 7, x = - 7

b. l2xl = 32

l2xl ÷ 2 = 32 ÷ 2

lxl = 16

x = 16, x = - 16

c. lx + 7l = 10

<u>x + 7 = 10</u>

<u>x + 7 = - 10</u>

x + 7 = 10

x + 7 - 7 = 10 - 7

x = 3

x + 7 = - 10

x + 7 - 7 = - 10 - 7

x = - 17

d. 5lxl = 35

<u>5x = 35</u>

<u>5x = - 35</u>

5x = 35

5x ÷ 5 = 35 ÷ 5

x = 7

5x = - 35

5x ÷ 5 = - 35 ÷ 5

x = - 7

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Delicious77 [7]

Answer:

The correct answer is that there will be 45 remaining apples.

Step-by-step explanation:

So, you start off with 89 and then you take 72 away, that leaves you with 17 apples. Then, you buy 14 more which brings it up to 31. After that, you give 12 more away which brings your total down to 19. Next, you go out and buy 42 more, which adds up to  61 remaining apples. Finally, you give away 16 more, which brings you to a grand total of, 45 apples left.

Hope this helps!

Rate 5 star and give brainliest!

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4 years ago
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Answer:

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Step-by-step explanation:

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Suppose the heights of 18-year-old men are approximately normally distributed, with mean 65 inches and standard deviation 4 inch
Serhud [2]

Answer:

Step-by-step explanation:

<u>a)</u>

  • Given that ; X ~ N ( µ = 65 , σ = 4 )
  • P ( 64 < X < 66 )

From application of normal distribution ;

  • Z = ( X - µ ) / σ, Z = ( 64 - 65 ) / 4,  Z = -0.25
  • Z = ( 66 - 65 ) / 4,  Z = 0.25

Hence, P ( -0.25 < Z < 0.25 ) = P ( 64 < X < 66 ) = P ( Z < 0.25 ) - P ( Z < -0.25 ) P ( 64 < X < 66 ) = 0.5987 - 0.4013

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b) X ~ N ( µ = 65 , σ = 4 )

  • P ( 64 < X < 66 )

From normal distribution application ;

  • Z = ( X - µ ) / ( σ / √(n)), plugging in the values,
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  • Z = ( 66 - 65 ) / ( 4 / √(12)) = Z = 0.866

P ( -0.87 < Z < 0.87 )

  • P ( 64 < X < 66 ) = P ( Z < 0.87 ) - P ( Z < -0.87 )
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  • P ( 64 < X < 66 ) = 0.6135

c) From the values gotten for (a) and (b), it is indicative that the probability in part (b) is much higher because the standard deviation is smaller for the x distribution.

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