Answer:
c) 4
Step-by-step explanation:
<u><em>The sum of two numbers is 14. The larger number minus three times the lesser number is -2</em></u>
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To solve this question, we need to write the statement mathematically;
Let the two numbers be x and y
"The sum of two numbers is 14" can be mathematically written as x+y = 14
and
"The larger number minus three times the lesser number is -2" can be mathematically written as x - 3y = -2
x + y = 14 ------------------(1)
x - 3y= -2 -------------------(2)
Subtract equation (2) from equation (1)
[x - x = 0 y - (-3y)=4y 14-(-2)=16]
4y = 16
To get the value of y divide both-side of the equation by 4
4y/4 = 16/4
y = 4
Substitute y=4 into equation (1)
x + y =14
x +4 =14
Subtract 4 from both-side of the equation
x + 4 -4 = 10]-4
x = 10
x=10 and y =4
Therefore the lesser number is 4
1) Distribute 8(2x-14) + 13 = 4x - 27 then simplify like terms to get: 16x - 99 = 4x - 27.
2) Subtract 4x on both sides and at the same time add 99 to both sides to get: 12x=72.
3) Divide both sides by 12 to get x=6.
PART B: 6 makes the equation true because you just solved for it.
Answer:
8/x = x/20
x^2=160
x=sqrt(160)
x=sqrt(16*10)
x=sqrt(16)*sqrt(10)
x=4*sqrt(10)
Step-by-step explanation:
Answer:
Y-3 = 2(x+1)
open the brackets
Y-3 = 2x+2
Y = 2x+5..... this is the answer when solving for Y
if were solving for x:
Y-3 = 2x+5
Y-8 = 2x
