An integer n>1 is abundant if the sum of its proper divisors is greater n. find the smallest abundant integer.

1 answer:

3 0

You can obviously skip over all the prime numbers. Take 4, 6, 8, 9, 10, 12, 14, etc.

4 only has two proper divisors: 1, 2
sum = 3

6 has three: 1, 2, 3
sum = 6

8 also has three: 1, 2, 4
sum = 7

10 has three: 1, 2, 5
sum = 8

12 has five: 1, 2, 3, 4, 6
sum = 16

12 is the least abundant integer.

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