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3 years ago

Rewrite the quadratic function in vertex form. Y=3x^2-12x+4

Mathematics

2 answers:

Shtirlitz [24]3 years ago

7 0

Answer:

y = 3(x - 2)² - 8

Step-by-step explanation:

The equation of a quadratic in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

To obtain this form use the method of completing the square

• The coefficient of the x² term must be 1

Factor out 3 from the first 2 terms

y = 3(x² - 4x ) + 4

• add/subtract (half the coefficient of the x- term )² to x² - 4x

y = 3(x² + 2(- 2)x + (- 2)² - (- 2)² ) + 4 ← complete the square

y = 3(x - 2)² - 12 + 4

y = 3(x - 2)² - 8 ← in vertex form

nataly862011 [7]3 years ago

6 0

Answer:

y=3(x-2)^2-8 I'm pretty sure

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Step-by-step explanation:

Given

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3 years ago

Triangle RST is shown. What is the y-coordinate of the final image of vertex T after the triangle is reflected over the x-axis f

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Answer:

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Step-by-step explanation:

Step(i):-

From the graph, the points are R(-4,5), S(1,3),T(-2,-2)

First, the points are reflected over the x-axis then transform in to

(x,y)→(x,-y)

R(-4,5)→R¹(-4,-5)

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T(-2,-2)→T¹(-2,2)

Step(ii):-

Next, The points are shifted to 3 units left then the transform

(x,y)→ (x -3 ,y)

R¹(-4,-5)→ R¹(-4-3, -5) → R¹(-7, -5)

S¹(1,-3) → S¹(1-3, -3) → S¹(-2, -3)

T¹(-2,2) → T¹(-2-3, 2)→ T¹(-5, 2)

Step(iii):-

Now again the points are shifted to '2' units up then transform to

(x,y) )→ (x ,y+2)

R¹(-7, -5+2) → R¹(-7, -3)

S¹(-2, -3+2) → S¹(-2, -1)

T¹(-5, 2+2) → T¹(-5, 4)

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