If the vectors are 4i-6j and -i-5j then the angle between both the vectors is approximately 45°.
Given two vectors be 4i-6j and -i-5j.
We are required to find the angle between vectors 4i-6j and -i-5j.
A vector is basically an equation involving a linear combination of vctors with possibly unkown coefficients. Vector is basically a quantity that has both magnitude and direction but not possition.
Angle is basically measure of inclination of something with the surface.
The angles between two vectors can be find out by the following formula:
cos Θ=[dot product of both the vectors/(product of magnitude of both the vectors)
cos Θ=[4*(-1)+(-6)*(-5)]/
cos Θ=(-4+30)/
cos Θ=26/
cos Θ=26/26.77
cos Θ=0.7070
Θ=(0.707)
Θ=45.008
Approximately 45°.
Hence if the vectors are 4i-6j and -i-5j then the angle between both the vectors is approximately 45°.
Learn more about vectors at brainly.com/question/25705666
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You have to do 200 divided by 20 your answer is ten
Taking the observation point as a vertex. The line to the observed window is the hypotenuse of a right triangle formed with the horizontal distance between the two buildings and the opposite leg to the angle of elevation.
The tangent of this angle is the ratio between the opposite leg and the adjacent leg. And the opposite leg is also the height from the height of the observation window to the observed window.
If h is the height from ground level to the second window, we will call h - 40 to the opposite leg and d to the adjacent leg that is also the horizontal distance between the buildings.
tangent(43º) = 0,93251509 = (h - 40)/d
h = tangent(43º)*d + 40 feet = 0,93251509*110 feet + 40 feet = 142.58 feet
Answer = C.) = 140 feet above the ground level is the second window.
No if the circles center is not also the center of the sphere then the circle is a small circle.