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Lemur [1.5K]
3 years ago
15

How do you do a expression

Mathematics
1 answer:
8090 [49]3 years ago
5 0
1. get rid of your parenthesis 
2. in order to do so you must look inside of the parenthesis and check if you have any like terms if so combine them
3. next use the distribution property or otherwise known as the rainbow
4. if you have an exponent to the right of your parenthesis then use the exponent rule
5. combine like terms by adding coefficients
6. finally combine the constants





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How to find area of a rectangle?
anyanavicka [17]

Formula

Area = L*w


Hint : To find the area of a rectangle , multiply the length times the width


I hope that's help !


4 0
3 years ago
Estamate 12871+6281+5146 by first rounding each number to the nearest thousand.
Pie
12,871 rounded to nearest thousand = 13,000.

6281 rounded to nearest thousand = 6,000.

5146 rounded to nearest thousand = 5,000.

In total, 13,000 + 6,000 + 5,000 = 24,000.
4 0
4 years ago
Can someone please help me
Umnica [9.8K]

9514 1404 393

Answer:

  • central: XWR, VWU
  • inscribed: VST

Step-by-step explanation:

Point W is the center of the circle. Any angle with W as its vertex is a central angle:

  angles XWR and VWU are central angles

Any angle with its vertex on the circle and rays that intersect the circle is an inscribed angle.

  angle VST is an inscribed angle

7 0
3 years ago
If a person high jumps 6 feet 8 inches, how many inches is the jump?
LenaWriter [7]

Answer:

80 inches

Step-by-step explanation:

6 x 12 = 72 + 8= 80

Give brainliest please

6 0
3 years ago
Read 2 more answers
If you roll two fair dice repeatedly, what is the probability that you will get a sum of 4 before you get a sum of 5 ? (a) (b) (
AlexFokin [52]

Answer:

The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

Step-by-step explanation:

Given : If you roll two fair dice repeatedly.

To find : What is the probability that you will get a sum of 4 before you get a sum of 5 ?

Solution :

When two dice are rolled the outcomes are

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Total number of outcomes = 36

Favorable outcome get a sum of 4 before you get a sum of 5 is (1,3) ,(2,2) and (3,1) = 3

The probability that you will get a sum of 4 before you get a sum of 5 is

P=\frac{3}{36}

P=\frac{1}{12}

Therefore, The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

5 0
3 years ago
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