The plane flies a distance of approximately 10.536 kilometers in <em>straight</em> line and with a bearing of approximately 035°.
A plane that travels a distance 
, in kilometers, with a bearing of 
sexagesimal degrees can be represented in standard position by means of the following expression:
(1)
We can obtain the resulting vector (
) by the principle of superposition:
![\vec R = \Sigma_{i=1}^{n} [r_{i}\cdot (\sin \theta_{i}, \cos \theta_{i})]](https://tex.z-dn.net/?f=%5Cvec%20R%20%3D%20%5CSigma_%7Bi%3D1%7D%5E%7Bn%7D%20%5Br_%7Bi%7D%5Ccdot%20%28%5Csin%20%5Ctheta_%7Bi%7D%2C%20%5Ccos%20%5Ctheta_%7Bi%7D%29%5D)
(2)
If we know that 
, 
, 
, 
, 
and 
, then the resulting vector is:
![\vec R = (5\sqrt{3}, 6) \,[km]](https://tex.z-dn.net/?f=%5Cvec%20R%20%3D%20%285%5Csqrt%7B3%7D%2C%206%29%20%5C%2C%5Bkm%5D)
The magnitude of the resultant is found by Pythagorean theorem:
And the bearing is determined by the following <em>inverse</em> trigonometric relationship:
(3)
If we know that 
and 
, then the magnitude and the bearing of the resultant is:
The plane flies a distance of approximately 10.536 kilometers in <em>straight</em> line and with a bearing of approximately 035°.
To learn more on vectors, we kindly invite to check this verified question: brainly.com/question/21925479
First do 2 1/2 / 5/8
5/2/ 5/8=2/5 * 5/8=1/4
now you can do anything with 1/4 so
your answer is 1/4
Answer:
y=-3x+4
Step-by-step explanation:
im assuming that you need the equation of the table
to find slope, y2-y1/x2-x1 10-4/-2-0
6/-2=-3 slope=-3
y=mx+b just sub in the numbers from a point in the table
10=-3(-2)+b
10=6+b
b=4
y=-3x+b
Answer:
B. W,V,Z
Step-by-step explanation:
Collinear points are two more points in the same plane that lie in a straight line.
From the diagram, Z is the intersection of the two diagonals of quadrilateral VXWY.
The points V, Z and W lie along the same diagonal, hence they are collinear.
The point y, Z, and X also lie along the same diagonal, these are also collinear.
The correct choice is B
