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3 years ago

Mp = 480 discount = 12 % find the sp

Mathematics

2 answers:

Karolina [17]3 years ago

8 0

Answer:

422.4

Step-by-step explanation:

MP=480

Discount%=12%

SP=?

We know that,

SP=MP-Discount%of MP

=480-12%×480

=480-57.6

=422.4

ddd [48]3 years ago

7 0

Step-by-step explanation:

hope it is helpful to you

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HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP(25 points)

miskamm [114]

Answer: I hope it helps :)

x=6 , y=6√3
x =23√3 , y=23
u =12 , v= 6
a =18√2 , b =18
x = 13 , y= 13

Step-by-step explanation:

$Hypotenuse =x\\Opposite =y \\Adjacent =6\\\alpha = 6\\Let's\: find\: the \:hypotenuse\: first\\Using SOHCAHTOA\\Cos \alpha = \frac{adj}{hyp} \\Cos 60 = \frac{6}{x} \\\frac{1}{2} =\frac{6}{x} \\Cross\:Multiply\\x = 12\\Let's\: find\: y\\Hyp^2=opp^2+adj^2\\12^2=y^2+6^2\\144=y^2+36\\144-36=y^2\\108=y^2\\\sqrt{108} =\sqrt{y^2} \\y=6\sqrt{3}$

$Opposite =x\\Hypotenuse = 46\\Adjacent =y \\\alpha =60\\Using \: SOHCAHTOA\\Sin \alpha =\frac{opp}{adj} \\Sin 60=\frac{x}{46}\\\\\frac{\sqrt{3} }{2} =\frac{x}{46} \\2x=46\sqrt{3} \\x = \frac{46\sqrt{3} }{2} \\x =23\sqrt{3} \\\\Hyp^2=opp^2+adj^2\\46^2=(23\sqrt{3} )^2+y^2\\2116=1587+y^2\\2116-1587=y^2\\529=y^2\\\sqrt{529} =\sqrt{y^2} \\y = 23$

$Hypotenuse = u\\Opposite =6\sqrt{3} \\Adjacent = v\\\alpha =60\\Sin\: 60 = \frac{6\sqrt{3} }{u} \\\frac{\sqrt{3} }{2} =\frac{6\sqrt{3} }{u} \\12\sqrt{3} =u\sqrt{3} \\\\\frac{12\sqrt{3} }{\sqrt{3} } =\frac{u\sqrt{3} }{\sqrt{3} } \\u = 12\\Hyp^2=opp^2+adj^2\\12^2= (6\sqrt{3} )^2+v^2\\144=108+v^2\\144-108=v^2\\36 = v^2\\\sqrt{36} =\sqrt{v^2} \\\\v =6$

$Hypotenuse = a\\Opposite =18 \\Adjacent = b\\\alpha =45\\Tan \alpha = opp/adj\\Tan \:45 =18/b\\1=\frac{18}{b}\\ b = 18\\\\Hyp^2=Opp^2+Adj^2\\a^2 = 18^2+18^2\\a^2=324+324\\a^2=648\\\sqrt{hyp^2} =\sqrt{648}\\ \\a =18\sqrt{2}$

$Hypotenuse = 13\sqrt{2}\\ Opposite =x\\Adjacent = y\\\alpha =45\\Sin\:\alpha = opp/hyp\\Sin 45=x/13\sqrt{2}\\ \\\frac{\sqrt{2} }{2} =\frac{x}{13\sqrt{2} } \\2x=26\\2x/2=26/2\\\\x = 13\\\\Hyp^2=opp^2+adj^2\\(13\sqrt{2})^2=13^2+y^2\\ 338=169+y^2\\338-169=y^2\\169=y^2\\\sqrt{169} =\sqrt{y^2} \\13 = y$

7 0

3 years ago

Joelle is working on a school report in a word processor. She wants to place a figure which is 13.09 wide so that it appears ce

Alinara [238K]

21.59-13.09= 8.5 cm
if its centered, it will same distance from the margin from the left and right.
So its distance from left or right margin is 8.5/2 = 4.25 cm

8 0

3 years ago

Read 2 more answers

Solve for x. 12x+252=324

Murrr4er [49]

Answer:

x = 6

Step-by-step explanation:

12x+252=324

Subtract 252 from each side

12x+252-252=324-252

12x =72

Divide each side by 12

12x/12 = 72/12

x =6

5 0

4 years ago

Read 2 more answers

A square and rectangle have the same area. The length of the rectangle is 5cm more than twice the length of the side of the squa

timurjin [86]

Answer:

10cm

Step-by-step explanation:

First let's define variables a and x:

a = area of rectangle and square

x = side of square

Now let's create an equation to calculate a using the square and an equation to calculate a using the rectangle:

Using square: $x^{2} =a$

Using rectangle: $(5+2x)(x-6)=a$

Now we want to solve for x so let's combine the equations since they are both equivalent to a

$(5+2x)(x-6)=x^{2}$

Simplify

$x^{2}-7x-30 = 0$

Solving this we get 10 and -3

Since it is impossible for a square to have a negative side value we can conclude that the value is 10cm

This can then be checked by plugging in 10 as x in our equations and seeing if we get the same a value:

Using square: $10^{2} = 100$

Using rectangle: $(5+2(10))(10-6) = (25)(4) = 100$

6 0

3 years ago

The equation of the line that contains diagonal HM is y = 2/3 x + 7.

nirvana33 [79]

Answer:

The slope of the line that contains diagonal OE will be = -3/2

Step-by-step explanation:

We know the slope-intercept form of the line equation

y = mx+b

Where m is the slope and b is the y-intercept

Given the equation of the line that contains diagonal HM is y = 2/3 x + 7

y = 2/3 x + 7

comparing the equation with the slope-intercept form of the line equation

y = mx+b

Thus, slope = m = 2/3

We know that the diagonals are perpendicular bisectors of each other.

As we have to determine the slope of the line that contains diagonal OE.

As the slope of the line that contains diagonal HM = 2/3

We also know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line.

Therefore, the slope of the line that contains diagonal

OE will be = -1/m = -1/(2/3) = -3/2

Hence, the slope of the line that contains diagonal OE will be = -3/2

3 0

3 years ago

Mp = 480 discount = 12 % find the sp​

Mp = 480 discount = 12 % find the sp