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evablogger [386]
3 years ago
15

Hihi !! need help fast please <3 <3

Mathematics
2 answers:
SashulF [63]3 years ago
6 0
It is 3 and 1/4 because i added it
Gelneren [198K]3 years ago
6 0

Answer:

3  1/4

Step-by-step explanation:

3/4+(1/3 divided by 1/6)-(-1/2)

1/3 divided by 1/6=2

3/4+2-(-1/2)

2+3/4= 2  3/4

2  3/4-(-1/2)

subtracting a negative is same as adding a positive

2  3/4+1/2=

3 1/4

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Reuben is making a replica of the us flag for his school project. he uses a scale of 0.5 centimeter to 1 inch to draw the flag.
Alex777 [14]
The question above makes use of the concept of ratio and proportion in a form of scaling. If we let x and y be the true length and width, the equations that best describe them are,
                                 0.5 cm / 1 inch = 2.5 cm / x in    ; x = 5 in
                                 0.5 cm / 1 inch = 4.75 cm / y in   ; y = 9.5 in
Therefore, the true length and width of Rueben's flag is 5 in and 9.5 in, respectively.
6 0
3 years ago
Read 2 more answers
The radius of a circle is 10 cm. What is the volume?
kobusy [5.1K]
The 3-dimensional shape of a circle is a sphere. In order to solve the volume (v) of a sphere from the radius or diameter of any circumscribed circle within is as follows:
v = 4/3 × pi × r^3, where pi roughly = 3.14
v = 4/3 × 3.14 × (10cm)^3
v = 1.33 × 3.14 × 1000cm^3
v = 4,188.56 cm^3 (cubic cm)
v = 4,189 cm^3 (rounded up)
3 0
3 years ago
Read 2 more answers
Please answer ASAP i need help please explain.
Phoenix [80]

Answer:

no

Step-by-step explanation:

3/4-2/3=9/12-8/12=1/12

4 0
3 years ago
2x-8≥-11 what is x in simplest form
xenn [34]
X is greater than or equal to 1.5
5 0
3 years ago
If &lt;ABC measures 100 and is inscribed in a circle O. find &lt;BAO and &lt;BCO​
satela [25.4K]

Answer:

<BCO​ = <BAO​ = 20degrees

Step-by-step explanation:

If <ABC measures 100 and is inscribed in a circle O. find <BAO and <BCO​

To get <BAO and <BCO​, we need to get <AOC first.

From the figure, it can be seen that triangle ABC is an isosceles trinagle. Hence;

<BAC + <BCA + 100 = 180

Since <BAC = <BCA

<BAC + <BAC = 180 - 100

2<BAC = 80

<BAC = 80/2

<BAC = 40

Also;

<BAO = <BCO​ and <BAO = <BAC/2

<BAO = 40/2 = <BCO​

Hence <BCO​ = <BAO​ = 20degrees

3 0
3 years ago
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