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3 years ago

PLS HELP ASAP

Mathematics

2 answers:

Paraphin [41]3 years ago

5 0

i think it’s -3 i’m sorry if i’m wrong..

daser333 [38]3 years ago

4 0

Answer:

-3/4 ÷ 2/-8 = 3 ( i think so! )

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A store sells cooking oil of two different brands in bottles of the same size. The table below and the equation each show the pr

Alexxandr [17]

Using the data, we can calculate the price per bottle for Brand A, which is:
24 / 2
= $12 per bottle

We also know that the slope of a line shows the rate of change, so the price per bottle for Brand B is $15.

The difference per bottle is 15 - 12 = Brand B is cost $3 more per bottle
The difference for 9 bottles will be: 9 * 3 = $27.

7 0

3 years ago

Tony buys a burger for $3 and a bottle of juice for $1.50 every day. Which expression shows the total amount he would spend on h

fomenos

It would be $22.50, because if you buy a burger for $3 and you get it for a 5 day period which would be $15. And then if you buy a juice for $1.50 for 5 days would be $7.50. So you would add $15 and $7.50 would be $22.50 for the whole 5 days.

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4 years ago

A line has a slope of - 4 and includes the points (6,v) and (3,3). What is the value of v?

labwork [276]

Answer: v = - 9

Step-by-step explanation:

Since two points on the line are given, we use formula for slope.

Let (a,b) and (c,d) be two points on the line, the slope of the line is given by

m= $\frac{d-b}{c-a}$ .

Hence, using this we have

-4= $\frac{3-v}{3-6}$

Thus, we have

-4×(-3)=3-v⇒12=3-v⇒12-3=-v⇒v=-9

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4 years ago

Hey, wanna pair our account on Brainly so we can share the perks? https://brainly.com/invite/7894ac0d941dd7582da9301dad223928?ut

Anastaziya [24]

Answer:

points for me too pls

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point

Maksim231197 [3]

Answer: $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

or (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

$\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]$

Taking square on both the sides , we get

$(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0$

Using quadratic formula : $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}$

so, $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

since $\sqrt{3}=1.732$

so, $(6+7(1.732),0)\text{ and }(6-7(1.732),0)$ are the required points.

i.e. (18.124,0) and ( -6.124,0) are the required points.

3 0

3 years ago