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2 years ago

HELP ASAP!right answer I’ll give you a crown

Mathematics

1 answer:

faltersainse [42]2 years ago

4 0

Answer:

$y=-\frac{3}{2}x+1$

Step-by-step explanation:

Slope-intercept form means

$y=mx+c$

where m is given its the slope which is $-\frac{3}{2}$ and we have the coordinates x and y which is (4, -5) and we need to find the value of c which is the y-intercept so we insert all these values into the equation so ,

$y=mx+c$

$-5 = -\frac{3}{2}(4)+c$

$-5=-6+c$

$c=1$

now we know the value of slope which is given $-\frac{3}{2}$ and we found the value of which is 1 so we put these values into our original slope-intercept form equation

$y=mx+c\\\\y=-\frac{3}{2}x+1$

You might be interested in

What is the range of the cubic function f(x)=x^3-15

Nina [5.8K]

B

The end behavior of a positive cubic function states that as x approaches infinity, y approaches infinity.

Similarly, as x approaches negative infinity, y approaches negative infinity.

This means that when written in interval notation, the range is (-inf, +inf).

3 0

2 years ago

Please show the steps

notka56 [123]

Answer:

x = -3, 0, or 7

Step-by-step explanation:

After removing common factors, the remaining quadratic can be factored by comparison to the factored form of a quadratic.

Write the equation in standard form.

4x³ -16x² -84x = 0

Factor out the common factor from all terms.

= 4x(x² -4x -21) = 0

Compare to the factored form of a quadratic:

(x +a)(x +b) = x² +(a+b)x +ab

This tells you the constants 'a' and 'b' in the factors can be found by considering ...

(a+b) = -4 . . . . the coefficient of the x term of the quadratic

ab = -21 . . . . . the constant term of the quadratic

It is often helpful to list factor pairs of the constant:

-21 = (-21)(1) = (-7)(3) . . . . integer pairs that have a negative sum

The sums of these pairs are -20 and -4. We are interested in the latter. We can choose ...

a = -7, b = 3

Put it all together.

4x³ -16x² -84 = (4x)(x -7)(x +3) = 0 . . . . . factored form of the equation

Apply the zero product rule. This rule tells you the product of factors will be zero when one or more of the factors is zero:

4x = 0 ⇒ x = 0

x -7 = 0 ⇒ x = 7

x +3 = 0 ⇒ x = -3

Solutions to the equation are x ∈ {-3, 0, 7}.

_____

<em>Additional comment</em>

What we did in Step 3 is sometimes referred to as the X-method of factoring a quadratic. The constant (ab product) is put at the top of the X, and the sum (a+b) is put at the bottom. The sides of the X are filled in with values that match the product and sum: -7 and 3. The method is modified slightly if the coefficient of x² is not 1.

A graphing calculator often provides a quick and easy method of finding the real zeros of a polynomial.

3 0

2 years ago

Help please help me I need this

mixer [17]

Answer:

$\frac{5+-\sqrt{53} }{2}$

Step-by-step explanation:

in the equation given these are the values:

a=1 b= -5 c= -7

if we plug this in the quadratic formula $\frac{-(-5)+-\sqrt{(-5)^2-4(1)(-7)} }{2(1)}$

this is simplified to $\frac{5+-\sqrt{53} }{2}$

hope this helped

3 0

3 years ago

Jamie is saving to buy a video game system. He has saved $16, which is 5% of the total cost. What is the cost of the video game

Galina-37 [17]

$320 5 times 20 is 100 so you have to times 16 by 20 to get the total 100% of the video game system

4 0

3 years ago

Need help on these !! 13 and 14! Please!!

katen-ka-za [31]

Question # 13

Answer:

The required equation for the given function is <em>y = 4sin(x/2+2π/3) -2 , as shown attached graph diagram.</em>

<em>Step-by-step explanation: </em>

As the general sine function is given by

$y=asin(bx+c)+d$ .......[A]

amplitude = a
period = 2π ÷ b
Phase shift = -c ÷ b
Vertical shift = d

As in the question,

amplitude = a = 4
period = 4π
phase shift = -4π/3
Vertical shift = d = -2

period = 2π ÷ b

b = 2π/period

b = 2π/4π ∵ period = 4π

b = 1/2

Also

Phase shift = -c/b

-4π/3 = -c/b ∵ phase shift = -4π/3

4π/3 = c/b

c = b × 4π/3

c = 1/2 × 4π/3

c = 4π/6

c = 2π/3

So, putting Amplitude ⇒ a = 4, Vertical shift ⇒ d = -2, b = 1/2 ,

and c = 2π/3 in Equation [A] would bring us the required equation for the given function.

$y=asin(bx+c)+d$

y = 4sin(x/2+2π/3)+(-2)

y = 4sin(x/2+2π/3) -2

<em>Note: The graph is also shown in attached diagram.</em>

Question # 14

<em>Answer:</em>

The required equation for the given function is y = cot(x+π/3)+2, as shown in attached graph diagram.

<em>Step-by-step explanation: </em>

As the general cotangent function is given by

$y=acot(bx+c)+d$ .......[A]

amplitude = a
period = π ÷ b
Phase shift = -c ÷ b
Vertical shift = d

As in the question,

period = π
phase shift = -π/3
Vertical shift = d = 2

period = π ÷ b

b = π/period

b = π/π ∵ period = 4π

b = 1

Also

Phase shift = -c/b

-π/3 = -c/b ∵ phase shift = -π/3

π/3 = c/b

c = b × π/3

c = 1 × π/3

c = π/3

So, putting vertical shift ⇒ d = 2, b = 1 and c = π/3 in Equation [A] would bring us the required equation for the given function.

$y=acot(bx+c)+d$

y = cot(x+π/3)+2

<em>Note: The graph is also shown in attached diagram.</em>

Keywords: amplitude, period , phase shift , vertical shift

Learn more about trigonometric functions of equations from brainly.com/question/2643311

#learnwithBrainly

7 0

3 years ago