The area of a triangular block is 49 square inches. If the base of the triangle is twice the height, how long are the base and t
he height of the triangle?
1 answer:
1) Formula: area = height * base / 2
2) Call x the height:
height = x
base = 2x
3) State the equation:
(x)(2x) = 49 in^2
4) Solve the equation:
2x^2 = 49 in^s
x^2 = (49/2) in^2
x = √(49/2) in
x = 7√2 / 2 in = 3.5 √2 in
5) Solution:
height = 3.5 √2 in and base = 7√2 in
6) Verification: area = (7√2 in) (3.5√2 in) = 49 in^2
Answer: height = 3.5√2 in and base = 7√2 in.
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