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konstantin123 [22]
2 years ago
5

Solve the following equation: 2x = 5

Mathematics
2 answers:
algol132 years ago
8 0

Answer:

2.5

Step-by-step explanation:

2 x 2.5 = 5

lutik1710 [3]2 years ago
4 0

Answer: x=2.5

Step-by-step explanation: Good luck! :D

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Points A, B, and C are plotted on the unit circle.
Sveta_85 [38]

Answer:

where is the circle?

Step-by-step explanation:

4 0
3 years ago
( 2 pts) Find the mean, median and mode of the data below, if possible: The responses of a sample of 1022 people who were asked
Dmitry [639]

The data is categorical data

Since the data is categorical data so it's become impossible to calculate either mean or median.

Now mode:

The data with the highest frequency is the mode.

So watchful is the mode because it contained 672 peoples

5 0
3 years ago
3 = q/11 i need it real quick
makkiz [27]

Answer:

q=33

Step-by-step explanation:

So we have:

3=\frac{q}{11}

Multiply both sides by 11:

11(3)=(11)\frac{q}{11}

The right side cancels:

11(3)=q

Multiply the left:

33=q

Thus, the value of q is 33.

7 0
2 years ago
Read 2 more answers
Help me plzzzz!!!!<br><br> Graph: y-3=1/2(x+2)
Zolol [24]

Answer:

Step-by-step explanation:

First you need to find the Slope Intercept form or find the point and slope.

The point is: (-2,3)

and the slope is: 1/2

y - 3 = 1/2(x + 2)

y - 3 = 1/2x + 1

y = 1/2x + 1 + 3

y = 1/2x + 4

Slope intercept form: y = 1/2x + 4

Graph is show below ---

                                       |

                                      V

8 0
3 years ago
The following probability distributions of job satisfaction scores for a sample of information
kodGreya [7K]

Answer:

a. 4.05 b. 3.84 c. 1.2475 and 1.1344 d. 1.1169 and 1.0651  e. We can say that the overall job satistaction of senior executives and middle managers is about 4; however, there is more variability in the job satisfaction for senior executives than in the job satisfaction for middle managers.

Step-by-step explanation:

a. (1)(0.05)+(2)(0.09)+(3)(0.03)+(4)(0.42)+(5)(0.41) = 4.05

b. (1)(0.04)+(2)(0.1)+(3)(0.12)+(4)(0.46)+(5)(0.28) = 3.84

c. We compute the variances as follow: [(1)^2(0.05)+(2)^2(0.09)+(3)^2(0.03)+(4)^2(0.42)+(5)^2(0.41)] - 4.05^2 = 1.2475 and [(1)^2(0.04)+(2)^2(0.1)+(3)^2(0.12)+(4)^2(0.46)+(5)^2(0.28)]-3.84^2 = 1.1344

d. The standard deviation is the squared root of the variance, therefore, we have \sqrt{1.2475} = 1.1169 and \sqrt{1.1344} = 1.0651

e. The expected value of the job satisfaction score for senior executives is very similar to the job satisfaction score for middle managers. We can say that the overall job satistaction of senior executives and middle managers is about 4; however, there is more variability in the job satisfaction for senior executives than in the job satisfaction for middle managers.

4 0
3 years ago
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