5x– 4y = -10 y = 2x – 5 y = x =

A researcher wants to investigate the effect of weather on college students' study habits. On a sunny day, the researcher sits i

LekaFEV [45]

The investigation that was carried out by the researcher illustrates a one-shot case study.

<h3>What is a one-shot case study?</h3>

It should be noted that a one-shot case study simply means a research design where a single group is observed after experiencing some treatment on a single occasion.

Since the researcher sits in the quad and records the number of minutes each student puts into studying, it's a one-shot case study.

Here, the single group of individuals are selected for observation.

Learn more about case study on:

brainly.com/question/15164693

6 0

3 years ago

On blueprint of a house, 48 millimeters represents 9 meters. The actual length of the living room is 6 meters. What is its lengt

Temka [501]

The blueprint length (b) will be
.. (6 m)/(9 m) = b/(48 mm)
.. b = (48 mm)*2/3
.. b = 32 mm

8 0

4 years ago

-11equals -2 plus x over 4

Afina-wow [57]

X= -36
1/4x-2=-11 Add 2 to both sides
1/4x=-9 multiply each side by 4
x=-36

8 0

3 years ago

Read 2 more answers

Solve each equation.SHOW work plz

Studentka2010 [4]

$3 \frac{1}{2} r = 28 \\ \frac{7}{2} r = 28 \\ \frac{ \frac{7}{2} }{ \frac{7}{2} } r = \frac{28}{ \frac{7}{2} } \\ r = \frac{ \frac{56}{2} }{ \frac{7}{2} } \\ r= \frac{56}{7}$

$1 \frac{1}{2} c =6 \\ \frac{3}{2} c= \frac{12}{2} \\ \frac{ \frac{3}{2} }{ \frac{3}{2} } c= \frac{ \frac{12}{2} }{ \frac{3}{2} } \\ c= \frac{ \frac{12}{2} }{ \frac{3}{2} } = \frac{12}{3} =4 \\ c=4$

7 0

3 years ago

A physician wants to develop criteria for determining whether a patient's pulse rate is atypical, and she wants to determine whe

valkas [14]

Answer:

a) 66.1 < μ < 82.7

b) 71.9 < μ < 97.7

c) D. No, because the two confidence intervals overlap, we cannot conclude that the two population means are different.

Step-by-step explanation:

Confidence interval is given by the formula

M±t×( $\frac{s}{\sqrt{N} }$ ) where

M is the sample mean
t is the corresponding t value for 95 confidence level
s is the sample standard deviation
N is the sample size

a. Construct a 95% confidence interval estimate of the mean pulse rate for males.

For men:

M=74.4 t=2.262 s=11.6207 N=10 then confidence interval is:

74.4±2.262×( $\frac{11.6207}{\sqrt{10 } }$ ) ≈ 74.4±8.3

b. Construct a 95% confidence interval estimate of the mean pulse rate for females.

For women:

M=84.8 t=2.262 s=18.0488 N=10 then confidence interval is:

84.8±2.262×( $\frac{18.0488 }{\sqrt{10 } }$ ) ≈ 84.8±12.9

c. Compare the preceding results. Can we conclude that the population means for males and females are different?

Difference of Population means for males and females are not statistically significant, since confidence intervals overlap.

4 0

3 years ago