Answer:
Step-by-step explanation:
Hello,
You can list the following ones which are correct for a), b) and c)
Thanks
Answer:
The three digit number = 951
Step-by-step explanation:
Let suppose the numbers are:
= abc
According to given condition:
a+ b + c = 15 -------------eq1
Also, given the difference between the first two digit = the difference between the last two digits:
==> l a-b l = l b-cl
==> (a-b) = (b-c)
==> (a+c) = 2b
Now we will substitue in eq1
==> a+ b + c = 15
==> 2b + b = 15
==> 3b = 15
Dividing both sides by 3 we get:
b =5
a + c = 2b
a+ c = 10
a = 10 -c ..........(2)
We know that"
(a-b) = (b-c)
==> a > b+c
==> a > 5 + c
==> 10 -c > 5 +c
==>5 > 2c
==> 2.5 > c
As c is an odd number so c will be equal to 1
c = 1
a = 10 -1
a = 9
The three digit number = 951
The hundred digit is greater than the sum of the tens and ones digits
i hope it will help you!
Standard form of polynomial = ax² + bx + c
Zeros: x = {-2,3}
This gives the factors as, (x + 2) (x - 3)
On expanding this:
(x + 2) (x - 3)
x(x - 3) + 2(x - 3)
x² - 3x + 2x - 3
x² - x - 3
Polynomial = <em>x² - x - 3</em>
