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2 years ago

6

Does anyone know what 98x1892 is? I’m to lazy to solve and my head hurts sooo bad please help! And we can’t use calculators we h

ave to have our cams on !

2 answers:

aliina [53]2 years ago

8 0

Answer:

185,416 this is the answerr

katrin [286]2 years ago

7 0

Answer:

Step-by-step explanation:

185416

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Find the tenth term of the expansion (x+ y)¹³

Anon25 [30]

Answer:

$715x^4y^9$

Step-by-step explanation:

Given

$(x + y)^{13$

Required

Determine the 10th term

Using binomial expansion, we have:

$(a + b)^n = ^nC_0a^nb^0 + ^nC_1a^{n-1}b^1 + ^nC_2a^{n-2}b^2 +.....+^nC_na^{0}b^n$

For, the 10th term. n = 9

So, we have:

$(a + b)^n = ^nC_{9}a^{n-9}b^{9$

$(x + y)^{13} = ^{13}C_{9}x^{13-9}y^9$

$(x + y)^{13} = ^{13}C_{9}x^4y^9$

Apply combination formula

$(x + y)^{13} = \frac{13!}{(13-9)!9!}x^4y^9$

$(x + y)^{13} = \frac{13!}{4!9!}x^4y^9$

$(x + y)^{13} = \frac{13*12*11*10*9!}{4!9!}x^4y^9$

$(x + y)^{13} = \frac{13*12*11*10}{4!}x^4y^9$

$(x + y)^{13} = \frac{13*12*11*10}{4*3*2*1}x^4y^9$

$(x + y)^{13} = \frac{17160}{24}x^4y^9$

$(x + y)^{13} = 715x^4y^9$

Hence, the 10th term is $715x^4y^9$

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2 years ago

The length of a rectangular picture is 6 inches less than twice the width. if the perimeter is 60 inches, find the dimensions of

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I think it's like 16 or 10. this is a weird word problem

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3 years ago

Which algebraic expression represents the following:the sum of four times a number and six?

Drupady [299]

Four times a number -- 4x

sum (+) of 4 times a number and 6

4x + 6

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2 years ago

Kwan has determined that he can use the expression 2(n+1)−3 to find the number of squares for any step number n. Find an equival

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Answer:

the answer is 2n-1

Step-by-step explanation:

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2 years ago

Martin had 7 pounds of grapes left, and he gave away 2/5 of them. Explain how to use compatible numbers to estimate the amount o

Dima020 [189]

<span>2/5 is close to 1/2, and it is easy to find 1/2 of 7 mentally. Half of 7 is 3.5, so Martin gave away about 3.5 pounds.</span>

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3 years ago

Read 2 more answers