Based on the data provided, we can conclude that the graph in question corresponds to the K-selected theory in regards to the human species. 
When considering the data of certain species and grouping them into categories such as extinct, endangered, or K/r-selected we take into account factors such as: 
- Population size
- Behavior 
- Carrying capacity
- Reproduction rates
and so on, then classify each species accordingly. 
Species that are Extinct are no longer on the earth. This classification refers to species of the past and does not include humans as of yet. The endangered category is reserved for species whose population sizes are <u>at a critical low and are near </u><u>extinction</u>, which is also not the case for humans. 
The K-selected and r-selected theories consider reproduction rates and carrying capacity as well when grouping species. Species that produce few offspring at a time are often found in this group. This category also refers to species whose offspring have a high chance of survival into maturity and whose population size is near the limit of the environment. All of this follows the data given and is the classification for the human species. 
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It carries deoxygenated blood from the right ventricle to the lungs
        
                    
             
        
        
        
The difference<span> between the </span>birth rate<span> and the death </span>rate<span> of a country or place is called the </span>natural increase<span>. </span>
        
             
        
        
        
Answer:
6,25%
Explanation:
Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:
Parents: Aa X Aa
Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)
Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:
A x A = 1/4 = 25%
A x a = 1/4 = 25%
a x A = 1/4 = 25%
a x a = 1/4 = 25%
The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:
1/4 × 1/4 = 1/16 = 0.0625 = 6.25%
It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.
 
        
             
        
        
        
Answer:
Pulmonary circulation
Explanation:
The pulmonary artery is a big artery that comes from the heart, so it splits into two main branches, and brings blood from the heart to the lungs.