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ladessa [460]
3 years ago
6

Find the area of the sector of the circle with radius 2 meters and central angle 11pi over 6

Mathematics
1 answer:
Natali [406]3 years ago
5 0
Area=r^2\theta/2

A= (2)^2\cdot 11\pi/12=11\pi/3
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Combine like terms to create an equivalent expression.
Brut [27]

Question..

Combine like terms to create an equivalent expression.

½ −⅙q +⅚q - ⅓

Answer:

½ −⅙q +⅚q - ⅓ is equivalent to ⅔q + ⅙

Step-by-step explanation:

Given

½ −⅙q +⅚q - ⅓

Required

Equivalence

½ −⅙q +⅚q - ⅓

We start by collecting like terms.

⅚q - ⅙q + ½ - ⅓

Factorize

(⅚ - ⅙)q + ½ - ⅓

((5 - 1)/6)q + ½ - ⅓

(4/6)q + ½ - ⅓

Reduce 4/6 to lowest term

⅔q + ½ - ⅓

Evaluate fraction

⅔q + (3 - 2)/6

⅔q + ⅙

Hence, ½ −⅙q +⅚q - ⅓ is equivalent to ⅔q + ⅙

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$11.25

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2 years ago
Can someone help.
r-ruslan [8.4K]

Answer:

m∠C = 38°  (nearest whole number).

Step-by-step explanation:

To find the missing angle, use the Sine Rule.

<u>Sine Rule</u> (for angles)

\sf \dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c}

where:

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  • a, b and c are the sides opposite the angles

Given:

  • A = 53°
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To find m∠C, substitute the given values into the formula and solve for C:

\implies \sf \dfrac{\sin 53^{\circ}}{18}=\dfrac{\sin C}{14}

\implies \sf \sin C= \dfrac{14 \sin 53^{\circ}}{18}

\implies \sf C= \sin^{-1} \left( \dfrac{14 \sin 53^{\circ}}{18}\right)

\implies \sf C= 38.40096301...^{\circ}

Therefore, m∠C = 38°  (nearest whole number).

Learn more about the sine rule here:

brainly.com/question/27089170

brainly.com/question/27704834

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2 years ago
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Identify each shape as translation, rotation and reflection​
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