The answer to the problem is x=2
=4/3 * 3.14 * 4.8³
=12.56/3 *110.592
=1389.0355/3
=463.01183
ie, 463 cubic inches(approx.)
Answer:
C. 17.6
General Formulas and Concepts:
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Trigonometry</u>
- [Right Triangles Only] SOHCAHTOA
- [Right Triangles Only] tanθ = opposite over adjacent
Step-by-step explanation:
<u>Step 1: Identify Variables</u>
Angle θ = 40°
Opposite Leg = <em>x</em>
Adjacent Leg = 21
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute in variables [tangent]:
![\displaystyle tan(40^\circ) = \frac{x}{21}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20tan%2840%5E%5Ccirc%29%20%3D%20%5Cfrac%7Bx%7D%7B21%7D)
- [Multiplication Property of Equality] Isolate <em>x</em>:
![\displaystyle 21tan(40^\circ) = x](https://tex.z-dn.net/?f=%5Cdisplaystyle%2021tan%2840%5E%5Ccirc%29%20%3D%20x)
- Rewrite:
![\displaystyle x = 21tan(40^\circ)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%20%3D%2021tan%2840%5E%5Ccirc%29)
- Evaluate:
![\displaystyle x = 17.6211](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%20%3D%2017.6211)
- Round:
![\displaystyle x \approx 17.6](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%20%5Capprox%2017.6)
![K(1,4)\rightarrow K^{\prime}(-1,4)](https://tex.z-dn.net/?f=K%281%2C4%29%5Crightarrow%20K%5E%7B%5Cprime%7D%28-1%2C4%29)
Explanation
Step 1
find the coordinate of every point of the quadrilateral
C(-3,1)
J(0,1)
K(1,4)
M(4,-2)
Step 2
When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite (its sign is changed).
so
![(x,y)\rightarrow reflect\text{ across y -Ax is}\rightarrow(-x,y)](https://tex.z-dn.net/?f=%28x%2Cy%29%5Crightarrow%20reflect%5Ctext%7B%20across%20y%20-Ax%20is%7D%5Crightarrow%28-x%2Cy%29)
therefore
![\begin{gathered} C\mleft(-3,1\mright)\rightarrow C^{\prime}(3,1) \\ J\mleft(0,1\mright)\rightarrow J^{\prime}(0,1) \\ K\mleft(1,4\mright)\rightarrow K^{\prime}(-1,4) \\ M(4,-2)\rightarrow M^{\prime}(-4,-2) \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20C%5Cmleft%28-3%2C1%5Cmright%29%5Crightarrow%20C%5E%7B%5Cprime%7D%283%2C1%29%20%5C%5C%20J%5Cmleft%280%2C1%5Cmright%29%5Crightarrow%20J%5E%7B%5Cprime%7D%280%2C1%29%20%5C%5C%20K%5Cmleft%281%2C4%5Cmright%29%5Crightarrow%20K%5E%7B%5Cprime%7D%28-1%2C4%29%20%5C%5C%20M%284%2C-2%29%5Crightarrow%20M%5E%7B%5Cprime%7D%28-4%2C-2%29%20%5Cend%7Bgathered%7D)
so, the answer is
![K^{\prime}(-1,4)](https://tex.z-dn.net/?f=K%5E%7B%5Cprime%7D%28-1%2C4%29)
i hope this helps you
Answer:
If we are choosing students at random from all students who got a B:
Total number of non-female students who got a B: 19
Total number of students who got a B: 36
Probability: 19/36
If we are choosing students at random from all students:
Total number of non-female students who got a B: 19
Total number of students: 78
Probability: 19/78