<h2>
Answer with explanation:</h2>
Given : The proportion of New Zealanders consume five or more servings of soft drinks per week :
a) The number of survey respondents reported that they consume five or more servings of soft drinks per week = 2006
b) Confidence interval for population proportion (p) :

, where
= Sample proportion.
n= Sample size.
z* = Critical value.
For n= 2006 ,
and critical value for 95% confidence interval : z* = 1.96
Then , the required confidence interval will be :






i.e. A 95% confidence interval for the proportion of New Zealanders who report that they consume five or more servings of soft drinks per week. = 
c) 
176\times100\%)[/tex]
d) The estimate might be biased because the survey is taken online that means offline New Zealanders are out of consideration.
Answer:
24x4 24 divided by 4 24+ 4 it should be one of these hope this helps
Step-by-step explanation:
First rounding off the both values..
Answer = 53300 * 600
= 31980000
%age error = [(53300*600 - 53320*599) / (53320*599) ]*100
=0.1%
Yeah i think so because
5-2=3
3+2=3
?
70-20=50
50+20=70
idek