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1 year ago

I need help on this maths question

Mathematics

1 answer:

loris [4]1 year ago

4 0

All I saw there was area so just multiply 10.2 and 17 which is 173.4

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What is 2,345 rounded to the nearest 10

ser-zykov [4K]

2,350 Hope this helped

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3 years ago

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English

larisa86 [58]

Answer:

6 square feet

Step-by-step explanation:

Carpet has w= 8 ft and l = 12 ft

Reduced carpet has w' = 2 ft

Reduction factor is

8/2 = 4

Then

l' = l/4 = 12/4 = 3 ft

Area of small carpet

S = 2*3 = 6 ft²

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3 years ago

The integral represents the volume of a solid. describe the solid. π π 0 sin(x) dx

Oxana [17]

Is that all the question says ??

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2 years ago

Need help as soon as possible

choli [55]

Answer:

Sin(F) = 12/13

Cos(F) = 5/13

Tan(F) = 12/5

Step-by-step explanation:

Sin = Opp./Hypo, Cos = Adj./Hypo. and Tan = Opp./Adj.

Sin(F) = Opp./Hypo = 12/13

Cos(F) = Adj./Hypo = 5/13

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7 0

3 years ago

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If a = √3-√11 and b = 1 /a, then find a² - b²

Serga [27]

If $b=\frac1a$ , then by rationalizing the denominator we can rewrite

$b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8$

Now,

$a^2 - b^2 = (a-b) (a+b)$

and

$a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8$

$a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8$

$\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}$

5 0

1 year ago