The 2nd one, with the pink is correct it is reflecting across the x axis
There are two ways to do this but the way I prefer is to make one of the equations in terms of one variable and then 'plug this in' to the second equation. I will demonstrate
Look at equation 1,

this can quite easily be manipulated to show

.
Then because there is a y in the second equation (and both equations are simultaneous) we can 'plug in' our new equation where y is in the second one

which can then be solved for x since there is only one variable

and then with our x solution we can work out our y solution by using the equation we manipulated

.
So the solution to these equations is x=-2 when y=6
Answer:
C) (square root 2)/2
Step-by-step explanation:
In quadrant III, the sine of an angle is positive. The value will be ...
sin(Θ) = √(1 -cos(x)^2) = √(1 -(-√2/2)^2) = √(2/4)
sin(Θ) = (√2)/2
Use the distance formula?
<span>b. A linear equation with slope 5 and y-intercept 1 c. A linear equation with slope 2 and y-intercept 3 d. A linear equation with slope 3 and y-intercept 2
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