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kifflom [539]
3 years ago
12

Which of the ordered pairs below could be in this Function?

Mathematics
1 answer:
DochEvi [55]3 years ago
6 0
I believe it is.... (2,2)or(4,4)
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35 points in 20 minutes or 49 points in 35 minutes? Find which is greater.
Vitek1552 [10]

Answer:

35 points in 20minutes is greater than 49 points in 35 minutes.

7 0
3 years ago
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Write an equation that describes the function.
a_sh-v [17]
4x is the proportionality
7 0
2 years ago
In 1997, the American Diabetes Association (ADA) and the federal government lowered the standard for diagnosing diabetes from a
Klio2033 [76]

Answer:

10 percent

Step-by-step explanation:

- Before 1997, people with a minimum FBGL of 140mg/dl were diagnosed as diabetic

- After 1997, people with a minimum FBGL of 126mg/dl were diagnosed as diabetic

- What is the proportion of people who were not considered diabetic before 1997 but are now considered diabetic (after 1997)?

140 - 126 = 14

In percentage, this proportion is = 14/140 × 100

= 10%

Hence, 10% of the people who were not considered diabetic before 1997 are now or will now be considered diabetic.

3 0
3 years ago
Which expression shows a sum of three terms.
vladimir1956 [14]

Answer:  B) 3+y+3

This can be simplified to y+6, but the current un-simplified expression has 3 terms.

======================================

Explanation:

Terms are separated by a plus sign. If you had something like 10x-5y, then you would write that as 10x+(-5y) showing that 10x and -5y are the two terms.

Choices A and C, xy and 6y respectively, have one term each. They are considered monomials. Mono = one, nomial = name.

Choice D is the product of the constant 3 and the binomial y+3. Binomials have two terms.

Only choice B has three terms, though we can simplify it down to two terms. I have a feeling your teacher doesn't want you to simplify it.

5 0
3 years ago
Giải các phương trình vi phân sau<br> y' - y/x+1 = 2
KatRina [158]

It looks like the differential equation is

y'-\dfrac y{x+1}=2

Multiply both sides by 1/(<em>x</em> + 1) :

\dfrac{y'}{x+1}-\dfrac y{(x+1)^2} = \dfrac2{x+1}

The left side is now a derivative of a product,

\left(\dfrac y{x+1}\right)' = \dfrac2{x+1}

Integrate both sides with respect to <em>x</em> :

\dfrac y{x+1} = 2\ln|x+1|+C

Solve for <em>y</em> :

y = 2(x+1)\ln|x+1| + C(x+1)

3 0
3 years ago
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