Answer:
2m
Step-by-step explanation:


Answer:
B = 1320

Step-by-step explanation:
Let A = number of students at Branch A
Let B = number of students at Branch B
If the number of students taking classes at Branch A is 1/4 more than Branch B, then:


If Branch A has 1,650 students, then substitute A = 1650 and solve for B:





The sum of the first four terms of the sequence is 22.
In this question,
The formula of sum of linear sequence is

The sum of the first ten terms of a linear sequence is 145
⇒ 
⇒ 145 = 5 (2a+9d)
⇒ 
⇒ 29 = 2a + 9d ------- (1)
The sum of the next ten term is 445, so the sum of first twenty terms is
⇒ 145 + 445
⇒ 
⇒ 590 = 10 (2a + 19d)
⇒ 
⇒ 59 = 2a + 19d -------- (2)
Now subtract (2) from (1),
⇒ 30 = 10d
⇒ d = 
⇒ d = 3
Substitute d in (1), we get
⇒ 29 = 2a + 9(3)
⇒ 29 = 2a + 27
⇒ 29 - 27 = 2a
⇒ 2 = 2a
⇒ a = 
⇒ a = 1
Thus, sum of first four terms is
⇒ 
⇒ 
⇒ S₄ = 2(2+9)
⇒ S₄ = 2(11)
⇒ S₄ = 22.
Hence we can conclude that the sum of the first four terms of the sequence is 22.
Learn more about sum of sequence of n terms here
brainly.com/question/20385181
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Answer:
i think it would be A
Step-by-step explanation:
You can buy 8 posters with 48.00 19.20x2=38.40 the leftover change isn’t enough to buy more