If 476 miles equates to 14 gallons, to find the gallons needed for 578 miles, you multiply 578 * 14 which is 8092, then divide that by 476 = 17
17 gallons of gas.
Answer:
4
2 + 2 = 4
took me longer then I expected
The parallel line:
y = mx + c
y = 5/7x + 7
Gradient of parallel line = 5/7
y = mx + c
y = 5/7x + c
-2 = (5/7 x -5) + c
-2 = -25/7 + c
-2 + 25/7 = c
c = 11/7
y = 5/7x + 11/7
The perpendicular line
y = mx + c
y = 5/7x + c
m = 5/7
Gradient of perpendicular line = -1/(5/7) = -7/5
y = mx + c
y = -7/5x + c
-2 = (-7/5 x -5) + c
-2 = 7 + c
-2 - 7 = c
c = -9
y = -7/5x - 9
<span>3t - 2/3=1+t
we need to separate t. subtract t from both sides.
2t - 2/3 = 1
add 2/3 to both sides.
2t = 1+2/3
2t = 3/3 + 2/3
2t = 5/3
divide 2 by both sides.
t = 5/6</span>
You can use the Law of Cosines, if only one of which is missing: three sides and one angle. Hence, if the known properties of the triangle is SSS(side-side-side) or SAS (side-angle-side), this law is applicable.
You can use the Law of Sines if you want to equate the ratio of the sine of an angle and its opposite side. This can be used if the known properties of the triangle is ASA(angle-side-angle) or SAS.
The ambiguous case is the SAS triangle. This could be easily solved using Law of Sines than Law of Cosines. Take for example: side a = 4, side b = 10, angle A = 23°. Then, we can determine angle B through Sine Law.
sin 23°/4 = sin B/10
B = 77.64°
