All categories

3 years ago

The slope of the line

Mathematics

1 answer:

Fantom [35]3 years ago

6 0

Answer: -2

Explanation: On the image we can see it goes down 4 units and right 2. Giving us the slope $\frac{-4}{2}$

Simplified that is -2 which is the slope of the line

You might be interested in

What is the slope of the line passing<br> through the points (-6, 2) and (-6,<br> 11)?

Mamont248 [21]

-3/4 is the slope.
Explanation: if we use the formula y2- y1/ x2-x1= m (m being the slope) we get -3/4.

5 0

2 years ago

Write the ratio 3/7 to 9 as a fraction in simplest form

AleksAgata [21]

Answer:

soory i need more points

Step-by-step explanation:

7 0

2 years ago

Prove: If a^2-a is even then a is even.

Alla [95]

This is not always true. Consider $a=3$ . Then $3^2-3=9-3=6$ is even, but $a$ is odd.

6 0

3 years ago

Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.

Sindrei [870]

Answer:

a) $P(X=3) = 0.1$

b) $P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

c) $P(X=4) = 0.3$

d) $P(X=0) = 0.2$

e) $E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

f) $E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

Step-by-step explanation:

We have the following distribution

x 0 1 2 3 4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

$P(X=3) = 0.1$

Part b

We want this probability:

$P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

Part c

For this case we want this probability:

$P(X=4) = 0.3$

Part d

$P(X=0) = 0.2$

Part e

We can find the mean with this formula:

$E(X)= \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

Part f

We can find the second moment with this formula

$E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

4 0

3 years ago

1. What does c(3) = 60 mean in terms of the problem?

drek231 [11]

C=20 I think the answer is that

3 0

3 years ago