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nalin [4]
3 years ago
6

There are 100 people in a wedding house, including children, men and women, and there are 100 pappadas to give with Sadya Te.

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
8 0

Answer:

Two possible sets of answers.

5 men, 11 women and 42 children, or

10 men, 2 women and 88 children

Selamat Sadhya!

Step-by-step explanation:

M = number of men

W = number of women

100-M-W = number of children

Total number of pappadas

5M+3W+(100-M-W)/2 = 100

Solve for W

W = (100-9M)/5 .......................(1)

Examine equation (1).

In order to have W as a whole number, M must be multiple of 5

Therefore M = 5 or 10

If M = 5, W = (100-45)/5 = 11 and children = 100-5-11 =  84

If M = 10, W = (100-90)/5 = 2 and children = 100-10-2 = 88

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SOLUTION:

Step 1:

From the given question, and comparing the scores in classes A and B

Step 2:

Question one, to know the class which had the better overall result on the exam;

(I) The scores in class A ranges from 65 to 100, while that of class B ranges from 60 to 90. This explains that class A had better results.

(ii) The median of the scores in class A is 85, while the median of the scores in class B is 75, this is another piece of supporting evidence that class A had better results.

Step 3:

Question two, to know the class which had greater variability in the results;

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Step 4:

So we need to find the range of scores in each of the two classes and then compare, the class with the greater range has the greater variability.

The Range is the difference between the lowest and highest score (H - L), where H is the highest score and L is the lowest score.

Step 5:

Applying the formula for range stated in step 4;

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