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Georgia [21]
2 years ago
15

Describing the technologies used in diffrent generation of computer​

Computers and Technology
1 answer:
kupik [55]2 years ago
8 0

Windows 98, Windows XP, Windows vista, Windows 7, Windows 8 y Windows 10.

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The Windows Net use command is a quick way to discover any shared resources on a computer or server. True or False
V125BC [204]
Yes it’s true the window net use command is a quick way to discover any shared resources on a computer or server
8 0
2 years ago
What is an easy and accurate way that a graphic designer can increase the size of a digital shape while keeping the ratio of hei
VikaD [51]

Answer:

Open the shape’s properties window, and type the height value multiplied by 2 and the width value multiplied by 3.

Explanation:

7 0
3 years ago
Read 2 more answers
Write a function named dice_eval that accepts two parameters representing numeric dice values and returns a string describing th
Zigmanuir [339]

Following are the "dice_eval" method code into python language.

Program Explanation:

  • Defining a method "dice_eval" that takes two variables "d1,d2" in its parametes.
  • Inside the method, multiple conditional statements were used that adds the parameter values and calculates its value which can be defined as follows:
  • In the if block, it adds the parameters and uses or gate that check its value that is equal to 7 or 11. so, it will return a string message that is 'Winner!'.  
  • In the elif block, it adds the parameters and uses or gate that check its value that is equal to 2 or 3 or 12. so, it will return a string message that is ' C r aps ! '.
  • In the else block, it uses a return keyword that adds parameter value and prints a string value.
  • Outside the method "d1,d2" is declared that inputs the value from the user-end, and passes the value into the method, and prints its value.

Program:

def dice_eval(d1, d2):#defining a method dice_eval that takes two parameters

if (d1+d2)==7 or (d1+d2)==11:#defining if block that adds parameter value and use or operator to check its value

return 'Winner!'#return string value

elif (d1+d2)==2 or (d1+d2)==3 or (d1+d2)==12:#defining elif block that adds parameter value and use or operator to check its value

return 'C r aps!'#return string value

else:#defining else block

return 'Point is '+str(d1+d2)#return string value with adding parameter

d1=int(input())#defining d1 that input value

d2=int(input())#defining d2 that input value

print(dice_eval(d1,d2))#calling method and print its return value

Output:

Please find the attached file

Please find the complete code in the attached file.

Learn more:

brainly.com/question/15011927

4 0
3 years ago
write a program, using python, to determine the mean, median, and standard deviation of a list of numbers. In addition, count th
Mekhanik [1.2K]

Answer:

The program to this question can be given as:

Program:

import math   #import packages

import sys

number =  [3, 6, 7, 2, 8, 9, 2, 3, 7, 4, 5, 9, 2, 1, 6, 9, 6]  #define list  

n = len(number)   # taking length of list

print("Sample Data: ",number)  #print list

#find Mean

print("Mean is: ")  #message  

add = sum(number)  # addition of numbers.

mean = add / n  #add divide by total list number.

print(str(mean))  #print mean

number.sort()   #short list by using sort function

#find Median

print("Median is: ")

if n % 2 == 0:        #conditional statement.

   median1 = number[n//2]  

   median2 = number[n//2 - 1]  

   median = (median1 + median2)/2

else:  

   median = number[n//2]  

print(str(median)) #print median

#find Standard deviation.

print("Standard Deviation :")

def SD(number):  #define function SD

   if n <= 1:      #check condition

       return 0.0   #return value.

   mean,SD = average(number), 0.0  

   # find Standard deviation(SD).

   for j in number:

       SD =SD+(float(j)-mean)**2

       #calculate Standard deviation holing in variable SD  

       SD =math.sqrt((SD)/float(n-1))#using math sqrt function.

   return SD  #return value.

def average(av):         #define function average

   n,mean =len(av), 0.0  

   if n <= 1:

       return av[0]   #return value.

   # calculate average

   for I in av:

       mean +=float(i)

       mean /= float(n)

   return mean             #return value.

print(SD(number)) #print value

Output:

Sample Data:  [3, 6, 7, 2, 8, 9, 2, 3, 7, 4, 5, 9, 2, 1, 6, 9, 6]

Mean is:  

5.235294117647059

Median is:  

6

Standard Deviation :

2.140859045465338

Explanation:

In the above python program first, we import packages to perform maths and other functions. Then we declare the list that is number in the list the elements are given in the question. Then we declare variable n in this variable we take the number of elements present in the list and print the list first. In the list, we perform three operations that can be given as:

Mean:  

In the mean operation firstly we define the variable add in this variable we add all elements of the list by using the math sum function then we divide the number by number of elements present in the list. and sore the value in the mean variable and print it.

Median:

In the median section firstly we sort the list by using the sort function. Then we use the conditional statements for calculating median. In the if block first we modules the number by 2 if it gives 0. it calculates first and second median the add-in median .else it will print that number.

Standard Deviation:

In the standard deviation part first, we define two functions that is SD() function and average().In the SD() function we pass the list as the parameter. In this function we use the conditional statement in the if block we call the average() function and use for loop for return all values. In the average() function we calculate the average of the all number and return value. At last, we print all values.

7 0
3 years ago
A = [2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 33 34 35 36 37 38 39 40]
vova2212 [387]

Answer:

C = a./b

Explanation:

In MATLAB, the following command:

C = A./B

Performs the element by elemet division of A and B. This comand is called Right-array division.

So, in your case, we could divide A by B element by element, only using fully-vectorised code (ie. no loops), with the following code:

a = [2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 33 34 35 36 37 38 39 40];b = [1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 43 45 47 49 50 54 59 60];C = a./b;

C would be the element by element division of A and B, with no loops.

5 0
3 years ago
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