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noname [10]
3 years ago
11

Can you answer this in picture form, please?

Mathematics
2 answers:
babunello [35]3 years ago
8 0

Answer:

It may be Arrow diagram yes or not

Pachacha [2.7K]3 years ago
7 0

Answer:

Step-by-step explanation:

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What is the answer for 2= -7 + s?
djyliett [7]

Answer:

9

Step-by-step explanation:

2 = -7 + s -->

9 = s

3 0
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Which of these is considered a concurrent power?
scoundrel [369]

Answer:

d - collecting taxes should be the answer

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3 years ago
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PLEASE HELP!! LMNP is rotated 90° clockwise around the origin. What are the coordinates of M’
lubasha [3.4K]

Answer:

The answer is "(4, -5)".

Step-by-step explanation:

Please find the complete question in the attached file.

In the given image file when we rotate it to 90 degrees clockwise so the value as the rule is (x, y) \longrightarrow (y, -x)

Putting the value in x = 5 and y = 4 then:

(5, 4) \longrightarrow (4, -5)

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3 years ago
Givin the area of a square is 225 square feet, what is the length of each side
Romashka [77]
The area of a square is calculated by squaring the length of the sides (multiplying by itself).  Therefore, in order to find the length, you must find the square root of 225. 

The square root of 225 is 15.  Therefore, you length of each side is 15 feet. 


p.s. I don't know how old you are, but I would recommend trying to memorise your square numbers up to 17^{2} .  I know I found that incredibly useful when it came to my exams last year (GCSEs)

7 0
4 years ago
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Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.
Sindrei [870]

Answer:

a) P(X=3) = 0.1

b) P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

c) P(X=4) = 0.3

d) P(X=0) = 0.2

e) E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

f) E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

Step-by-step explanation:

We have the following distribution

x      0     1     2   3   4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

P(X=3) = 0.1

Part b

We want this probability:

P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

Part c

For this case we want this probability:

P(X=4) = 0.3

Part d

P(X=0) = 0.2

Part e

We can find the mean with this formula:

E(X)= \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

Part f

We can find the second moment with this formula

E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

4 0
4 years ago
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