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lutik1710 [3]
3 years ago
12

Which statement describes the solution to the system of equations?

Mathematics
1 answer:
Lena [83]3 years ago
4 0

For this case:

D.-) The system has infinitely many solutions.

<h2>Explanation:</h2>

Remember that you have to write complete questions in order to find exact and good answers. In this exercise, the system is missing. However, I'll provide the following system:

\text{\ensuremath{\left.\begin{array}{c}(1)\\(2)\end{array}\right.\left\{ \begin{array}{c}3x+y=-6\\6x+2y=-12\end{array}\right.}}

So we have two equations and two variables. Our first equation is:

3x+y=-6

And the second equation is:

6x+2y=-12

When graphing these two lines, we can get the following possibilities:

  • They have a unique solution. This means the graphs intersect at a single point.
  • They have infinitely many solutions. This implies the lines are basically the same.
  • They have no solution. This implies they are parallel but with different y-intersect.

By dividing equation (2) by 2 we get:

\frac{6x+2y}{2}=\frac{-12}{2} \\ \\ 3x+y=-6

So we get the same equation as line (1), so <em>the conclusion is that they have infinitely many solutions.</em>

<h2>Learn more:</h2>

Infinitely many solutions: brainly.com/question/13771057

#LearnWithBrainly

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Please help me with this asap!!!!!!!!!!!!!!!!!!!!!!!!!!
drek231 [11]
Try the first four cards in order from left to right. It starts with the expression, plugs in 6 for t, does 6 * 3 first because of PEMDAS, and then does 27 - 18, which is 9.
3 0
2 years ago
Explain how to determine it a function is exponential growth or exponential decay. Give an example of each.
kozerog [31]

Answer: Formula is given in the picture Step-by-step explanation: For the exponential growth we have the formula Exponential functions are in the form  y = ab^ xIf  a is positive and b  is greater than  1, then it is exponential growth. If a is positive and b is less than 1 but greater than 0, then it is exponential decay. For Example2 months ago you had 3 mice, you now have 18 shows and exponential growth And Atmospheric pressure (the pressure of air around you) decreases as you go higher shows exponential decay.


Read more on Brainly.com - brainly.com/question/11678436#readmore


Step-by-step explanation


6 0
3 years ago
PLEASE HELP GUYS i am struggling so much, two questions
ankoles [38]

Answer: the equation of the standard parabola

1) (y-6)^2 = 4 (x-1)

The equation of the standard parabola

2) (x+5)^2 = 16(y-2)

Step-by-step explanation:

<u>Explanation </u>

<u>Parabola:-</u>

The set of points in a plane whose distance from a fixed point and a constant ratio to their corresponding perpendicular distance from a fixed straight line is a conic.

Let S be a fixed point and l be a fixed straight line from any point P,the perpendicular PM is drawn to the line 'l'

  • The locus of P such that \frac{SP}{PM} = constant
  • The fixed point  'S' is called the Focus.
  • The fixed line'l 'is called the directrix of the conic
  • The constant ratio is known as the eccentricity, denoted by 'e'
  • If e=1 , the conic is called a parabola

1) <u> Step 1</u> :-

Given the focus   S = (2,6) and directrix is x=0

we know that \frac{SP}{PM}=1

now cross multiplication , we get

SP = PM

squaring on both sides,we get

SP^{2} = PM^2

step 2:-

now using distance formula is

  • \sqrt(((x_{2}-x_{1})^2+(y_{2} -y_{1} )^2)

Given S =(2,6) and P(x,y) be any point on parabola

SP^2 = (x-2)^2+(y-6)^2........(1)

Now using perpendicular distance formula

let P(x , y ) be any point on the parabola

  • \frac{ax_{1}+by_{1}+c   }{\sqrt{a^2+b^2} }

Given the directrix is x =0 and P(x,y) be any point on parabola

PM^2 = \frac{x^2}{\sqrt{1}^2 }......(2)

equating equation(1) and equation (2), on simplification

we get (x-2)^2+(y-6)^2 = x^2.....(3)

  • apply (a-b)^2 = a^2+  b^2+2 ab

now the equation (3) is

(y-6)^2 = 4 x-4

now the standard form of parabola is

(y-k)^2 = 4 a(x-h)

<u>Final answer</u>:-

(y-6)^2 = 4 (x-1)

2) <u> Explanation:-</u>

<u>step 1:</u>

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

here the given points of 'x'co- ordinates are equal

  • Therefore the axis AS is parallel to y- axis

now the standard equation of parabola

(x-h)^2 = 4 a (y-k)

now you have to find' a' value

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

The distance of AS = \sqrt{(-5-(-5)^2+(2-6)^2}

 on simplification we get a =4

<u>Final answe</u>r :-

the vertex (h,k) = (-5,2) and a=4

(x-h)^2 = 4 a (y-k)

The standard parabola is (x+5)^2 = 16 (y-2)

5 0
3 years ago
If the sales tax of a state is 8%what is the price of a $400 punching bag
Aleks [24]
The answer is $432

Multiply 400 by .08 and you get 32, which you add to the original price.
8 0
3 years ago
Let f(x) = 3x2 - 6x + 2. Find f(-2)
Neporo4naja [7]

Answer:

just put

x =  - 2

f( x) = 3 {x}^{2}  - 6x + 2

f( - 2) = 3 {( - 2)}^{2}  - 6( - 2) + 2

f( - 2) = 3 \times 4 + 6 \times 2 + 2 =12+12+2 \\ f(-2)= 26

3 0
3 years ago
Read 2 more answers
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