Answer: When t = 4.25 R(t) = D(t)
This tells you that at 4.25 seconds into their flights, both the Rocket and the Drone were at a height of 20 feet.
Step-by-step explanation: The point where the two graphed lines cross is where the values are equal.
The Drone has been hovering at 20 feet between 2 and 5 seconds. The Rocket passed through that height for a brief (millisecond) time as it was falling back to the ground.
Without grid lines it is my best estimation (using a ruler to create a verticla line from the intersection of the lines to the time scale) that t = 4.25. It is between 4 and 4.5 seconds.
Answer:
99 (cm^2)
Step-by-step explanation:
Perpendicular to the AB segment at points D and C, the graph is divided into two triangles and a rectangle.
The area of the middle rectangle is equal to 8*9=72. The hypotenuse of the right triangle is 10cm, and one of the right sides is 9cm, so the other side is SQRT (10^2-9^2) = SQRT (19).
One side of the left triangle is 9cm long and the other side is 14-8-sqRT (19) = 6-sqRT (19) cm.
Then, add the area of the three parts.
72+9*sqrt（19）/2+9*（6-sqrt（19））/2=99 (cm^2)
17.5
5 is the og length. Scale factor is 3.5. So
5(3.5)=17.5
1) B
2) C
can you help me? since I helped you?
Answer:
x = -7
Step-by-step explanation:
-1 + x = -8
x = -7
