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tino4ka555 [31]
3 years ago
10

Can anyone answer this?

Mathematics
1 answer:
sukhopar [10]3 years ago
4 0

Answer:

n= 6. hope this helped as I tried my best.

Step-by-step explanation:

2³ × 2^n = 2⁹

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Solve kx+12=3kx for x
PilotLPTM [1.2K]

Answer:

x=6/k

Step-by-step explanation:

we have

kx+12=3kx

Solve for x

That means----> isolate the variable x

Subtract kx both sides

kx+12-kx=3kx-kx

12=2kx

Divide by 2k both sides

12/2k=2kx/2k

6/k=x

Rewrite

x=6/k

3 0
4 years ago
Read 2 more answers
A cereal box has a surface area of 280 square inches. What is the surface are of a similar box that is larger by a scale factor
ICE Princess25 [194]

Answer: 548.8 square inches

Step-by-step explanation:

From the question, we are informed that a cereal box has a surface area of 280 square inches.

The surface area of a similar box that is larger by a scale factor of 1.4 will be gotten by multiplying 280 by the scale factor's square. This will be:

= 280 × (1.4)²

= 280 × 1.96

= 548.8 square inches

5 0
3 years ago
Let A be a non-empty set of rational numbers and B = {a+1 : a ∈ A} (sometimes denotes A + 1). Prove carefully that sup(B) = sup(
liraira [26]

Answer:

a is an element of A; a is a rational number

(a+1) is element of B

Step-by-step explanation:

(a+1) = sup(A), which are the elements of B.

(a+1) + 1 = sup(B)

Recall a+1 = sup(A),

Therefore,

sup(A )+ 1 = sup(B)

sup(B) = sup(A) + 1 ___proved

Sup(A) means supremum of set A. It means least element of another set (say set B), that is greater than every element in set A

8 0
4 years ago
What is the discriminant of the quadratic equation: (multiple choice)
Dominik [7]

Answer:

85

Step-by-step explanation:

<em>The equation for the discriminant is </em>

b^2-4(a)(c)

<em>Plug your numbers in from the equation. </em>

<em>1=a, -7=b, -9=c</em>

<em />

(-7)^2-4(1)(-9)

49-(-36)

49+36

85

6 0
4 years ago
In 1998, as an advertising campaign, the Nabisco Company announced a "1000 Chips Challenge," claiming that every 18-ounce bag of
Phoenix [80]

Answer:

A 95% confidence interval for the mean number of chips in a bag of Chips Ahoy Cookies is [1187.96, 1288.44].

Step-by-step explanation:

We are given that statistics students at the Air Force Academy (no kidding) purchased some randomly selected bags of cookies and counted the chocolate chips.

Some of their data are given below; 1219, 1214, 1087, 1200, 1419, 1121, 1325, 1345, 1244, 1258, 1356, 1132, 1191, 1270, 1295, 1135.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                          P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean number of chocolate chips = \frac{\sum X}{n} = 1238.2

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 94.3

            n = sample of car drivers = 16

            \mu = population mean number of chips in a bag

<em>Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.131 < t_1_5 < 2.131) = 0.95  {As the critical value of t at 15 degrees of

                                             freedom are -2.131 & 2.131 with P = 2.5%}  

P(-2.131 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.131) = 0.95

P( -2.131 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.131 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.131 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.131 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.131 \times {\frac{s}{\sqrt{n} } } , \bar X+2.131 \times {\frac{s}{\sqrt{n} } } ]

                                   = [ 1238.2-2.131 \times {\frac{94.3}{\sqrt{16} } } , 1238.2+2.131 \times {\frac{94.3}{\sqrt{16} } } ]

                                   = [1187.96, 1288.44]

Therefore, a 95% confidence interval for the mean number of chips in a bag of Chips Ahoy Cookies is [1187.96, 1288.44].

7 0
3 years ago
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