(0, 2 )
to find the y-intercept, let x = 0 in the equation
x = 0 , then 10y = 20 ⇒ y = 2 ← ( y- intercept ) ⇔ (0, 2 )
17/24, this is going to be you’re answer
I don't quite understand your topic sentence however to my best knowledge This is what i've come up with:
Rectangle 1 and 3 are the same. The only known side is the width at 5 inches whilst the other is unknown so it will be h.
Rectangle 1 and 3 area are "5h"
Rectangle 2 has a width of 8 and a length of h. Its area is "8h"
Without triangles our TSA for the rectangles is: 2 X 5H + 8H = TSA
The triangles are both assumed to be the same are. To get the Are of one it is
![\frac{1}{2}*(B*H)](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%2A%28B%2AH%29%20)
Which = 12
Ans: TSA = 18H + 24
Write an equation: 21+5x=48.5;
Then solve for x: 5x=27.5, x=5.5