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sergeinik [125]
3 years ago
13

Find the length of AD. HELP MEEEE​

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
8 0

Answer:

5.42

Step-by-step explanation:

hope this helped!! :)

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What is product of 5.2 · 10^6 and 1.4 · 10^3
Andrei [34K]

Answer:

7280000000 or 7.28^9 (in scientific notation)

Step-by-step explanation:

this question is asking you to transfer numbers out of scientific notation and multiply them. 10^6 is 1 followed by 6 zeros (good trick to remember) or 1000000. when you multiply anything by a power of 10 you just add that many zeroes to it or move the decimal point one point to the left for every zero. so in this example it is 5.2 times 1000000 which is 5200000. we do the same for the other one and we get 1400. When we multiply these two values we get 7280000000 or 7.28^9

3 0
3 years ago
Let f(x) = 6x2 + 5 and g(x) = 3x - 5. Find f(g(0)).
professor190 [17]
First you do g(0):
g(0) = 3(0) -5
g(0) = -5
then you do f(-5):
f(-5) = 6(-5)2 +5
3 0
3 years ago
A car can travel 120 km in 2 hours.How long will it take the car to travel 300 km?
kakasveta [241]

We first find out time taken to travel for just 1 km

2hrs is equivalent to 120 minutes

120 km  = 120 min

1 km  =  x        (where x is the time taken to travel 1 km).

we simplify the equation by cross - multiplying the equation , so:

120  × x = 1 × 120  → 120x = 120  → x  = 120/120 → x = 1

So  the car covers 1km  in 1 minute

For 300 km the car will take 300 × 1 minute = 300 minutes

we convert minutes to hours by dividing by 60 → 300 / 60 = 5

Therefore the car will take 5 hours to cover 300 km.





8 0
3 years ago
Read 2 more answers
Find the magnitude of the gravitational force
Nitella [24]

Answer:

6849.4

Step-by-step explanation:

m(r)(r) mass and radius equals N

7 0
3 years ago
1/(x-1)x+1/x(x+1)+...+1/(x+9)(x+10)=11/12
nata0808 [166]

Notice that

\dfrac1{(x-1)x} = \dfrac1{x-1} - \dfrac1x \\\\ \dfrac1{x(x+1)} = \dfrac1x - \dfrac1{x+1} \\\\ \vdots \\\\ \dfrac1{(x+9)(x+10)} = \dfrac1{x+9} - \dfrac1{x+10}

That is, the <em>n</em>-th term (where <em>n</em> = -1, 0, 1, …, 9) in the sum on the left side has a partial fraction decomposition of

\dfrac{1}{(x+n)(x+n+1)} = \dfrac1{x+n} - \dfrac1{x+n+1}

and in the sum, some adjacent terms will cancel and leave you with

\dfrac1{(x-1)x} + \dfrac1{x(x+1)} + \cdots + \dfrac1{(x+9)(x+10)} = \dfrac1{x-1} - \dfrac1{x+10} = \dfrac{11}{12}

Now solve for <em>x</em>, bearing in mind that we cannot have <em>x</em> = 0, -1, -2, …, -10 :

\dfrac1{x-1} - \dfrac1{x+10} = \dfrac{11}{12}

Combine the fractions on the left side:

\dfrac{(x+10)-(x-1)}{(x-1)(x+10)} = \dfrac{11}{(x-1)(x+10)} = \dfrac{11}{12}

Then we must have

(x-1)(x+10) = x^2 + 9x - 10 = 12 \implies x^2+9x-22 = (x+11)(x-2) = 0

so that either <em>x</em> = 2 or <em>x</em> = -11.

4 0
3 years ago
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