Lets say our number is 237x8
2+3+7+8+x should be divisible by 6.
20+x should be divisible by 6.
x=4
Positive: 1/2
Negative -0.25
First, we get the standard error of the mean using
σm = σ / √N
= 5 / √100
= 0.5
Next, we subtract and add 1.96 standard deviations from the mean (since the confidence interval is 95%). So,
8 ±1.96 (0.5)
= 8 <span>± 0.98
The answer is
</span>E) 8±0.98
The space between the two spheres will be the volume of the larger sphere minus the volume of the smaller sphere. Given that the volume of any sphere is:
V=(4πr^3)/3 The space between to sphere of different radius and positioned about the same center is:
S=(4πR^3)/3-(4πr^3)/3 I used S=volume of space, R=larger radius and r=smaller radius...
S=(4π/3)(R^3-r^3), we are told that R=5 and r=4 so
S=(4π/3)(5^3-4^3)
S=(4π/3)(125-64)
S=(4π/3)(61)
S=244π/61
S=4π cm^3
S≈12.57 cm^3 (to nearest hundredth of a ml)
4x - 13 = 2x + 9
Add 13 to each side
4x = 2x + 22
Subtract 2x from both sides
2x = 22
Divide both sides by 2
x = 11
