How would I graph a line that contains the point (6,5) and has a slope of - 2/3 ?
2 answers:
Answer:
y=-2/3x+9
Step-by-step explanation:
Use point-slope formula:
y-y1 = m(x-x1)
y-5=-2/3(x-6)
y-5=-2/3x+4
y=-2/3x+9
You would then proceed to graphing this equation, as it is in slope intercept form now.
HTH :)
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