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bija089 [108]
3 years ago
13

How would I graph a line that contains the point (6,5) and has a slope of - 2/3 ?​

Mathematics
2 answers:
ddd [48]3 years ago
6 0

Answer:

y=-2/3x+9

Step-by-step explanation:

Use point-slope formula:

y-y1 = m(x-x1)

y-5=-2/3(x-6)

y-5=-2/3x+4

y=-2/3x+9

You would then proceed to graphing this equation, as it is in slope intercept form now.

HTH :)

Semenov [28]3 years ago
6 0
Y=-2/3x+5
Answer is
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y = -X + 4 is the equation for the line below

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3 years ago
A veterinarian collects data on the number of times race horses are raced during their careers. The veterinarian finds that the
SpyIntel [72]

Answer:

c. (12.12, 18.48)

Step-by-step explanation:

Hello!

The study variable is X: number of times a racehorse is raced during its career.

The average number is X[bar]= 15.3 and the standard deviation is S= 6.8 obtained from a sample of n=20 horses.

To estimate the population mean you need that the variable has a normal distribution, in this case, we have no information about its distribution so I'll assume that it has a normal distribution. With n=20 the most accurate statistic to use for the estimation is a Students-t for one sample, the formula for the interval is:

X[bar] ± t_{n-1;1-\alpha /2} * \frac{S}{\sqrt{20} }

t_{n-1;1-\alpha /2} = t_{19;0.975}= 2.093

[15.3 ± 2.093 * \frac{6.8}{\sqrt{20} }]

[12.12; 18.48]

Using a significance level of 95% you'd expect that the true average of times racehorses are raced during their career is included in the interval [12.12; 18.48].

I hope it helps!

8 0
3 years ago
When written in standard form, the product of (3+x) and (2x-5)
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