Set up fractions and solve them
SOLUTION
The mean is 4min
standard deviation is 1min
the z score is

where

then we have

The probability the call lasted less than 3 min will be
Therefore, the probability that (z < -1 ) is
[tex]\begin{gathered} Pr(z<-1)=Pr(0
Hence, the percentage of the calls that lasted less than 3 min is 16%
To find the answer first find the base number or 1% of $188 which is 1.88. Next find what percent is asking for 25% so multiply by 25 1.88 which is 47 so 47-188 = 141 this is one way to do it
The equation needed is (Surface area of a cube)
A=6×a<span>²
Therefore your answer would be...
</span>194.94 in.<span>³</span>