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Arada [10]
3 years ago
8

Find the distance between the points E(3,7) and F(6,5)

Mathematics
1 answer:
Vesna [10]3 years ago
4 0

Answer:

<h3>\boxed{ \bold{  \huge{ \boxed{ \sf{ \sqrt{13}  \:  \: units}}}}}</h3>

Step-by-step explanation:

Solution,

E ( 3 , 7 ) ⇒ ( x₁ , y₁ )

F ( 6 , 5 ) ⇒( x₂ , y₂ )

<u>Finding </u><u>the </u><u>distance </u><u>between </u><u>these</u><u> </u><u>points</u><u>:</u>

\boxed{ \sf{distance =  \sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} } }}

plug the values

⇒\sf{ \sqrt{ {(6 - 3)}^{2} +  {(5 - 7)}^{2}  } }

Calculate the sum or difference

⇒\sf{ \sqrt{ {3}^{2} +  {( - 2)}^{2}  } }

Evaluate the power

⇒\sf{ \sqrt{9 + 4} }

Add the numbers

⇒\sf{ \sqrt{13} } units

Hope I helped !

Best regards!!!

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Step-by-step explanation:

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5 0
2 years ago
If log(x + y) = log 3 + ½log x + ½log y, prove that x² + y² = 7xy​
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Answer:

See Explanation

Step-by-step explanation:

log(x + y) = log3 +  \frac{1}{2} logx+  \frac{1}{2} logy \\  \\ log(x + y) = log3 +    logx ^{\frac{1}{2}} +   logy ^{\frac{1}{2}}\\  \\  log(x + y) = log3 +    log(xy) ^{\frac{1}{2}} \\  \\ log(x + y) =  log[3(xy) ^{\frac{1}{2}}] \\  \\ x + y = 3(xy) ^{\frac{1}{2}} \\  \\ squaring \: both \: sides \\  {(x + y)}^{2}  =  \bigg(3(xy) ^{\frac{1}{2}} \bigg)^{2}  \\  \\  {x}^{2}  +  {y}^{2}  + 2xy = 9xy \\  \\  {x}^{2}  +  {y}^{2}  = 9xy - 2xy \\  \\   \purple{ \bold{{x}^{2}  +  {y}^{2}  = 7xy}} \\ thus \: proved

7 0
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3 years ago
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Answer:

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Lines given:

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x coordinate of intersection of given lines is:

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As per graph point (35/22, 3/22) is point B

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