Triangle PQR and triangle QRS have vertices P(-9,7) , Q(4,7) , R(4,-3), and S(-10,3) What is the area in square units of the qua
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The given function is a variable separable differential equation. Combine like terms, integrate, apply the appropriate limits, and express V in terms of t. This is done as follows:
dV/dt = -3(V)^1/2
dV/-3V^1/2 = dt
m here is the initial V which is 225. Then after integrating,
-2/3 (√V - √225) = t
-2/3 (√V - 15) = t
That is the expression for V at time t. I hope I was able to help. Have a good day.
dV/dt = -3(V)^1/2
dV/-3V^1/2 = dt
m here is the initial V which is 225. Then after integrating,
-2/3 (√V - √225) = t
-2/3 (√V - 15) = t
That is the expression for V at time t. I hope I was able to help. Have a good day.
We know that
the scale is <span>is 1/2 inch = 4 feet
using a graph tool
</span><span>the approximate measurements in the drawing are
</span>5 cm x 4 cm
convert to in
5/2.54--------> 1.97 in
4/2.54------> 1.57 in
convert drawing to actual
if 0.5 in---------> 4 ft
1.97in-------> X
X=1.97*4/0.5------> X=15.76 ft
if 0.5 in---------> 4 ft
1.57 in-------> X
X=1.57*4/0.5------> X=12.56 ft
<span>the approximate area of Quinto's bedroom is 12.56*15.76=197.95 ft</span>²
the answer is
the option C)192 ft²
the scale is <span>is 1/2 inch = 4 feet
using a graph tool
</span><span>the approximate measurements in the drawing are
</span>5 cm x 4 cm
convert to in
5/2.54--------> 1.97 in
4/2.54------> 1.57 in
convert drawing to actual
if 0.5 in---------> 4 ft
1.97in-------> X
X=1.97*4/0.5------> X=15.76 ft
if 0.5 in---------> 4 ft
1.57 in-------> X
X=1.57*4/0.5------> X=12.56 ft
<span>the approximate area of Quinto's bedroom is 12.56*15.76=197.95 ft</span>²
the answer is
the option C)192 ft²