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2 years ago

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Triangle PQR and triangle QRS have vertices P(-9,7) , Q(4,7) , R(4,-3), and S(-10,3) What is the area in square units of the qua

drilateral PQSR which is formed by two trangles?

1 answer:

larisa [96]2 years ago

7 0

Answer:

3.7

Step-by-step explanation:

.

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3/5 with an exponent of 4

nordsb [41]

Step-by-step explanation:

$\text{If is}\ \dfrac{3}{5}^4,\ \text{then}\ \dfrac{3}{5}^4=\dfrac{3\cdot3\cdot3\cdot3}{5}=\dfrac{81}{5}=16\dfrac{1}{5}\\\\\text{If is}\ \left(\dfrac{3}{5}\right)^4=\left(\dfrac{3}{5}\right)\left(\dfrac{3}{5}\right)\left(\dfrac{3}{5}\right)\left(\dfrac{3}{5}\right)=\dfrac{3\cdot3\cdot3\cdot3}{5\cdot5\cdot5\cdot5}=\dfrac{81}{625}$

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3 years ago

Convert 77 degrees in Fahrenheit to Celsius temperature using the formula . 72°C 61°C 35°C 25°C

faust18 [17]

Answer:

25º celsius

Step-by-step explanation:

The formula for converting fahrenheit to celsius is: Deduct 32, then multiply by 5, then divide by 9

77 - 32 = 45 x 5 = 225/9 = 25º

8 0

2 years ago

The general solution of 2 y ln(x)y' = (y^2 + 4)/x is

Sav [38]

Replace $y'$ with $\dfrac{\mathrm dy}{\mathrm dx}$ to see that this ODE is separable:

$2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}$

Integrate both sides; on the left, set $u=y^2+4$ so that $\mathrm du=2y\,\mathrm dy$ ; on the right, set $v=\ln x$ so that $\mathrm dv=\dfrac{\mathrm dx}x$ . Then

$\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v$

$\implies\ln|u|=\ln|v|+C$

$\implies\ln(y^2+4)=\ln|\ln x|+C$

$\implies y^2+4=e^{\ln|\ln x|+C}$

$\implies y^2=C|\ln x|-4$

$\implies y=\pm\sqrt{C|\ln x|-4}$

4 0

2 years ago

What is the degree of vertex B and G?

Marat540 [252]

Answer:

degree of vertex B = 2

degree of vertex g = 4

Step-by-step explanation:

Using given picture we need to find about what is the degree of vertex B and G.

In graph theory, we know that the degree (or valency) of a vertex of a graph is the number of edges incident to the vertex.

So we just need to count how many edges are incindent on vertex B and G.

From picture we see that number of edges incident on vertex B = 2

Hence degree of vertex B = 2

From picture we see that number of edges incident on vertex G = 4

Hence degree of vertex g = 4

6 0

3 years ago

The formula for the circumference of a circle is c= 2pi r, where r is the radius. Rearrange the formula to solve for our and sel

ratelena [41]

Answer: r = C/(2pi)

This is the same as writing $r = \frac{C}{2\pi}$

=========================================================

Explanation:

pi is some number (approximately 3.14) which means 2pi is also some number (roughly 6.28)

Saying c = 2pi*r means we have 2pi times r, and the result is the circumference c. To isolate r, we'll undo the multiplication. We'll undo it by dividing both sides by 2pi like so

C = 2pi*r

C/(2pi) = r

r = C/(2pi)

in which we can write it like $r = \frac{C}{2\pi}$

So whatever C is, we divide it over 2pi (aka roughly 6.28) to get the radius.

-----------------

Extra Info (Optional Section):

As an example, let's say the circumference of the circle is 628 feet. This means the distance around the circle is 628 feet. So C = 628 would lead to...

r = C/(2pi)

r = C/(6.28)

r = 628/(6.28)

r = 100

So the radius would be roughly 100 feet.

8 0

3 years ago