What is 3/5 + 1/10, 3/5+9/10, 1/4+5/6, 3/8+1/12, 2/5+2/7 in simplest form I will give brainliest for correct answer.

Mathematics

1 answer:

forsale [732]2 years ago

8 0

Answer:

7/10, 3/2, 13/12, 11/24, and 24/35

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Please help, tysm if you do :D

castortr0y [4]

Answer:

I think it is C I don't really know but try C

7 0

2 years ago

What is the simplified form of the following expression? 7(^3 square root 2x) - 3 (^3 square root 16x) -3 (^3 square root 8x)

Pachacha [2.7K]

Answer:

The third option listed: $\sqrt[3]{2x} -6\sqrt[3]{x}\\$

Step-by-step explanation:

We start by writing all the numerical factors inside the qubic roots in factor form (and if possible with exponent 3 so as to easily identify what can be extracted from the root):

$7\sqrt[3]{2x} -3\sqrt[3]{16x} -3\sqrt[3]{8x} =\\=7\sqrt[3]{2x} -3\sqrt[3]{2^32x} -3\sqrt[3]{2^3x} =\\=7\sqrt[3]{2x} -3*2\sqrt[3]{2x} -3*2\sqrt[3]{x}=\\=7\sqrt[3]{2x} -6\sqrt[3]{2x} -6\sqrt[3]{x}$

And now we combine all like terms (notice that the only two terms we can combine are the first two, which contain the exact same radical form:

$7\sqrt[3]{2x} -6\sqrt[3]{2x} -6\sqrt[3]{x}=\\=\sqrt[3]{2x} -6\sqrt[3]{x}$

Therefore this is the simplified radical expression: $\sqrt[3]{2x} -6\sqrt[3]{x}\\$

5 0

3 years ago

A string of decorative lights is 25 feet long. The first light on the string is 16 inches from the plug. The lights on the strin

joja [24]

25 feet = 25 x 12 = 300 inches

First light is at 16 inches.
300 - 16 = 284 inches

Find the rest of the bulbs:
284 ÷ 4 = 71

Total number of lights = 71 + 1 = 72

Answer 72 lights

8 0

3 years ago

Let f(x) = 3x - 10. Find the value of f(-3).

laiz [17]

Easy, sub -3 for x
f(-3)=3(-3)-10
f(-3)=-9-10
f(-3)=-19

the value of f(-3) is -19

6 0

2 years ago

One bar of candy A and two bars of candy B have 774 calories. Two bars of candy A and one bar of candy B contains 786 calories.

vampirchik [111]

◆ Define the variables:

Let the calorie content of Candy A = a
and the calorie content of Candy B = b

◆ Form the equations:

One bar of candy A and two bars of candy B have 774 calories. Thus:

a + 2b = 774

Two bars of candy A and one bar of candy B contains 786 calories

2a + b = 786

◆ Solve the equations:

From first equation,
a + 2b = 774
=> a = 774 - 2b

Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie

◆ Find caloric content:

Caloric content of candy B = 254 calorie

Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie

5 0

3 years ago