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3 years ago

A cross- country runner runs 10 km in 40 minutes. what is his average speed

Mathematics

2 answers:

KonstantinChe [14]3 years ago

7 0

The answer is 400 because you multiply it

dlinn [17]3 years ago

6 0

All you have to do is to find the unit rate at which this person runs.

It is

10 km
--------- = 1/4 km/min, or 1 km
40 min --------- , or 0.25 km/min
4 min

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I’m so confused !! PLS HELP ME, it’s due in like 5 mins ASAP

Tresset [83]

Answer:

its g

Step-by-step explanation:

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3 years ago

Use the regression calculator to compare the teams’ number of runs with their number of wins. a 2-column table with 9 rows. colu

-Dominant- [34]

The equation of the trend line is ŷ = 0.15x - 23.21

<h3>How to determine the average rate of change of the trend line?</h3>

The points are given as:

hr =>808, 768, 655, 684, 637, 619, 613, 609, 563

w => 93, 94, 66, 81, 86, 75, 61, 69, 55.

Using a graphing calculator, we have the following calculation summary:

Sum of X = 5956
Sum of Y = 680
Mean X = 661.7778
Mean Y = 75.5556
Sum of squares (SSX) = 50569.5556
Sum of products (SP) = 7547.1111

The regression equation is represented as:

ŷ = bX + a

Where:

b = SP/SSX

b = 7547.11/50569.56

b = 0.14924

a = MY - bMX

a = 75.56 - (0.15*661.78)

a = -23.20961

This gives

ŷ = 0.14924X - 23.20961

Approximate

ŷ = 0.15x - 23.21

Hence, the equation of the trend line is ŷ = 0.15x - 23.21

Read more about trend lines at:

brainly.com/question/2589459

4 0

2 years ago

Convert the polar coordinates (-3, -60°) to Cartesian coordinates.

notsponge [240]

Answer:

(1.5,-2.6)

Step-by-step explanation:

Given the polar coordinates (-3,60°).

Let our Cartesian coordinates be (x,y)

#We know that when converting the rectangular coordinates (x,y) to polar (r,θ), then:

$r=\sqrt{x^2+y^2}\\\\\therefore r^2=x^2+y^2\\\\\theta=tan^{-1}(y/x)\\\therefore tan \theta=y/x$

#Using the illustration above, we can express our polar coordinates as:

$-3=\sqrt{x^2+y^2}\\\\-60\textdegree=tan^{-1}(y/x}$

#Solve simultaneously to solve for x and y:

$(-3)^2=x^2+y^2\ \ \ \ \ \ \ \ \ \ i\\\\tan(-0\texdegree)=y/x\ \ \ \ \ \ \ \ ...ii\\\\y=x\ tan(-60\textdegree)\ \ \ \ \ \ \ ...iii\\\\\#substitute\ y \ in\ i\\\\(-3)^2=x^2+(x \ tan (-60\textdegree))^2\\\\9=x^2+3x^2\\\\x=\sqrt{9/4}=1.5\\\\y=1.5\ tan(-60\textdegree)=-2.5981\approx-2.6$

Hence, the Cartesian coordinates are (1.5,-2.6)

6 0

3 years ago

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loris [4]

It's really important that you aim to understand how to do these problems yourself, rather than "pay" others to do them for you. Why not ask for "directions" or "guidance," instead of for "answers?"

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3 years ago

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finlep [7]

120^ is the answer for this problem

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3 years ago