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seraphim [82]
3 years ago
13

#8 Please help Extra 100 points And brainliest

Mathematics
1 answer:
Lunna [17]3 years ago
4 0

Answer:

When x < 0 (Option 1)

Step-by-step explanation:

The answer to your question would be Option 1, or when x < 0. When you create a table with f(x) and g(x), they're only ever equal when x = 0, which is when f(x) and g(x) both equal 1. When the numbers go into negatives for each equation, f(x) becomes exponentially bigger. Making f(x) > g(x) true when x < 0.

Hope this helps!

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What is 1+1/2+2/3? Correct answer needed for a quiz.
aleksklad [387]

Answer:

13/6

Step-by-step explanation:

1+0.5=1.5=9/6

9/6+4/6=13/6

8 0
4 years ago
Read 2 more answers
Solve -6f + 13 = 2f - 11​
igor_vitrenko [27]

Answer:

f = 3

Step-by-step explanation:

Solve for f:

13 - 6 f = 2 f - 11

Subtract 2 f from both sides:

13 + (-6 f - 2 f) = (2 f - 2 f) - 11

-6 f - 2 f = -8 f:

-8 f + 13 = (2 f - 2 f) - 11

2 f - 2 f = 0:

13 - 8 f = -11

Subtract 13 from both sides:

(13 - 13) - 8 f = -13 - 11

13 - 13 = 0:

-8 f = -13 - 11

-13 - 11 = -24:

-8 f = -24

Divide both sides of -8 f = -24 by -8:

(-8 f)/(-8) = (-24)/(-8)

(-8)/(-8) = 1:

f = (-24)/(-8)

The gcd of -24 and -8 is -8, so (-24)/(-8) = (-8×3)/(-8×1) = (-8)/(-8)×3 = 3:

Answer:  f = 3

4 0
4 years ago
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The thickness of a plastic film (in mils) on a substrate material is thought to be influenced by the temperature at which the co
statuscvo [17]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if rising the process temperature reduces the thickness of the plastic film that coats a substrate material To do so, two samples of substrates are coated at different temperatures:

Sample 1

X₁: Thickness of the plastic film after the substrate is coated at 125F

n₁=11

X[bar]₁= 101.28

S₁= 5.08

Sample 2

X₂: Thickness of the plastic film after the substrate is coated at 150F

n₂= 13

X[bar]₂= 101.70

S₂= 20.15

Does the data support this claim? Use the P-value approach and assume that the two population standard deviations are not equal.

Now if the higher the heat, the thinner the thickness of the plastic coating, then the average thickness of the coating done at 150F should be less than the average thickness of the coating done at 125F, symbolically: μ₂ < μ₁

Then the hypotheses are:

H₀: μ₂ ≥ μ₁

H₁: μ₂ < μ₁

α:0.05 (there is no α level stated so I've chosen the most common one)

Assuming that both variables have a normal distribution since the population standard deviations are not equal, the statistic to use is the Welch's t-test:

t= \frac{(X[bar]_2-X[bar]_1)-(Mu_1-Mu_2)}{\sqrt{\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} } } ~~t_w

t_{H_0}= \frac{(101.7-101.28)-0}{\sqrt{\frac{(20.15)^2}{13} +\frac{(5.08)^2}{11} } } = 0.072

This test is one-tailed to the left, meaning that you'll reject the null hypothesis at small values of t. The p-value is also one-tailed and has the same direction as the test. To calculate it you have to first calculate the degrees of freedom of the Welch's t:

Df_w= \frac{(\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} )^2}{\frac{(\frac{S^2_1}{n_1})^2 }{n_1-1}+\frac{(\frac{S^2_2}{n_2} )^2}{n_2-1}  }

Df_w= \frac{(\frac{5.08^2}{11} +\frac{20.15^2}{13} )^2}{\frac{(\frac{5.08^2}{11})^2 }{10} +\frac{(\frac{20.15^2}{13} )^2}{12} } = 13.78

The distribution is a Student's t with 13 degrees of freedom, then you can calculate the p-value as:

P(t₁₃≤0.072)= 0.4718

Using the p-value approach, the decision rule is:

If the p-value ≤ α, the decision is to reject the null hypothesis.

If the p-value > α, the decision is to not reject the null hypothesis.

The p-value is greater than the significance level, so the decision is to nor reject the null hypothesis.

Using a significance level of 5%, there is no significant evidence to support the claim that the average thickness pf the plastic coat processed at 150F is less than the average thickness pf the plastic coat processed at 125F.

I hope you have a SUPER day!

4 0
3 years ago
At the supermarket , 6 mangoes cost 6.12
Grace [21]

Answer:

good to know. but what's the question?

4 0
3 years ago
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The correct answer is D but i don’t understand
iren [92.7K]
The answer depends on the way you solved it.

I am assuming you take the base on which you perceived to be: . 5 and height which is 2.


So you must've ended with 1

But in actuality, you need to use the equation above and plug in 1.5 and 1
Subtract them and you should get 1.25

Do the same to the other side, you should get 6.

.125 x 6  = .875

8 0
3 years ago
Read 2 more answers
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