Question

Three consecutive integers can be represented by n, n+1 and n+2. If the sum of three consecutive integers is 57, what are the integers?

Answer 1

Answer:

The sum of intigers are 57

Therefore,

n+n+1+n+2 =57

3+3n=57

3n=57-3

3n=54

n=54/3

n=18

Therefore,

n=18,

n+1=18+1=19

n+2=18+2=20

Your answer is 18,19,20

You can confirm it by adding them

If you are helped with my answer pls tag me brianliest I really want it... Plzz

THANK YOU........