Question

Rewrite in simplest radical form: x^4/5 / x^1/3 into a√x^b

Answer 1

Answer:

$\sqrt[15]{x^7}$

Step-by-step explanation:

If we have the expression

$\frac{x^{\frac{4}{5}}}{x^{\frac{1}{3}}}$, we have to think about exponent rules.

If we have $a^b \div a^c$, then the value will be equal to $a^{b-c}$.

So $\frac{x^{\frac{4}{5}}}{x^{\frac{1}{3}}}$ simplified will be $x^{\frac{4}{5} - \frac{1}{3}}$

Converting $\frac{4}{5}$ and $\frac{1}{3}$ into fifteenths (lcm) gets us $\frac{12}{15} - \frac{5}{15} = \frac{7}{15}$.

We can convert $x^{\frac{7}{15}}$ into a radical by taking the denominator root of x to the numerator.

$\sqrt[15]{x^7}$.

Hope this helped!