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3 years ago

What is the answer to this question

Mathematics

2 answers:

Gwar [14]3 years ago

7 0

Answer:

Step-by-step explanation:

podryga [215]3 years ago

7 0

The answer is A srry if I’m wrong

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A card is drawn from a standard 52-card deck. What is the probability that the card is a red jack, given that the card is a face

yarga [219]

Answer:

The answer is B

Step-by-step explanation:

only 20 chars.....

8 0

3 years ago

Angle x and angle y are complementary angles if angle y is 5 times the size of angle x .what is the value of x and y

Ivahew [28]

The values of x and y are 15 and 75, respectively

<h3>How to determine the values of x and y?</h3>

The statements are given as:

Angle x and angle y are complementary angles
Angle y is 5 times the size of angle x

These mean that

x + y = 90

y = 5x

Substitute y = 5x in x + y = 90

x + 5x = 90

Evaluate the sum

6x = 90

Divide by 6

x = 15

Substitute x = 15 in y = 5x

y = 5 *15

Evaluate

y = 75

Hence, the values of x and y are 15 and 75, respectively

Read more about complementary angles at

brainly.com/question/15604439

#SPJ1

6 0

2 years ago

Geometry, please help

andrew-mc [135]

Answer:

True

If the angles are equal A and B are parallel

7 0

3 years ago

Y=x.arctan(x)^1/2. find dy/dx. pls show steps

Whitepunk [10]

$y=x(\arctan x)^{1/2}$

Use the product rule first:

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dx}{\mathrm dx}(\arctan x)^{1/2}+x\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}$

$\dfrac{\mathrm dy}{\mathrm dx}=(\arctan x)^{1/2}+x\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}$

Use the chain rule to compute the derivative of $(\arctan x)^{1/2}$ . Let $z=(\arctan x)^{1/2}$ and take $u=\arctan x$ , so that by the chain rule

$\dfrac{\mathrm dz}{\mathrm dx}=\dfrac{\mathrm dz}{\mathrm du}\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm dz}{\mathrm du}=\dfrac{\mathrm du^{1/2}}{\mathrm du}=\dfrac12u^{-1/2}$

$\dfrac{\mathrm du}{\mathrm dx}=\dfrac{\mathrm d\arctan x}{\mathrm dx}=\dfrac1{1+x^2}$

$\implies\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}=\dfrac1{2(\arctan x)^{1/2}(1+x^2)}$

So we have

$\dfrac{\mathrm dy}{\mathrm dx}=(\arctan x)^{1/2}+\dfrac x{2(\arctan x)^{1/2}(1+x^2)}$

You can rewrite this a bit by factoring $(\arctan x)^{-1/2}$ , just to make it look neater:

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac1{2(\arctan x)^{1/2}}\left(2\arctan x+\dfrac x{1+x^2}\right)$

3 0

3 years ago

Solve the inequalities.<br> 1. 3t ≤ 27<br> 2. y - 5 ≥ 0<br> 3. x + 4 < 10

PIT_PIT [208]

Solving an inequality is just like solving a normal two step equation.

1. T is less than or equal to 9.

2. y is greater than or equal to 5.

3. x is less than 6.

6 0

3 years ago

Read 2 more answers