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Stels [109]
2 years ago
10

Letters that represent numbers are called ?

Mathematics
2 answers:
Ivahew [28]2 years ago
6 0

i believe its variables

STALIN [3.7K]2 years ago
5 0

The answer is "variables"

Hope this helps:))

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A phone company charges a base fee of $12 per month plus an additional charge per minute. The monthly phone cost C can be repres
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Answer:

It’s actually     m = (C - 12) /3     But I don’t see it in the 4 option you have.

Step-by-step explanation:

C = 12+ am

C - 12 = am

(C - 12) /a = m

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How much food would you get if you had 40 bannanas and 30 apples but you lost 20 of the 30 apples?
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Step-by-step explanation:

30-20=10

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Which circuit A or B, represents a series circuit?"<br><br> PLEASE HELP ILL MARK THE BRAINLY
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The horse on a carousel is 4.5 m from the central axis. if the carousel rotates at 0.14 rev/s , how long does it take the horse
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You plan to borrow $36,500 at a 7.7% annual interest rate. The terms require you to amortize the loan with 7 equal end-of-year p
erma4kov [3.2K]

The amount of interest you would be paying in Year 2 is: $2,492.62.

<h3>Interest</h3>

First step is to calculate the Equal Monthly Payment

Equal Monthly Payment=P×r×(1+r)^t/(1+r)^t-1

Where:

P=Principal=$36,500

r=Rate=7.7%

t=Time=7 years

Equal Monthly Payment=36,500×0.077×(1+0.077)^7÷(1+0.077)^7-1

Equal Monthly Payment=36,500×0.077×(1.077)^7÷(1.077)^7-1

Equal Monthly Payment=36,500×0.077×1.6807763÷1.6807763-1

Equal Monthly Payment=4,723.82/0.6807763

Equal Monthly Payment=$6,938.875

Second step is to calculate Year 1 Closing balance

Year 1 Closing balance  = Beginning  balance + Interest - EMI Payment

Year 1 Closing balance=  $36,500 +($36,500×7.7%) - $6,938.875

Year 1 Closing balance=  $36,500 + $2,810.5 -$6,938.875

Year 1 Closing balance =   $32,371.625

Third step is to calculate year 2 interest

Year 2 Interest= $32,371.625×7.7%

Year 2 Interest=$2,492.62

Therefore the amount of interest you would be paying in Year 2 is: $2,492.62.

Learn more about interest here:brainly.com/question/15259578

#SPJ1

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