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kari74 [83]
3 years ago
8

PLEASE HELP ASAP!!!!

Mathematics
1 answer:
mylen [45]3 years ago
6 0
I am pretty sure that the answer is 4/5, hope this helped :)

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Can someone help me solve this and explain it to me? <br> −1/6(x−18)+1/3(x+3)=x+4
KATRIN_1 [288]

Answer:

Below.

Step-by-step explanation:

So calculate.

-1/6x+3+1/3x+1=x+4.

Cancel equal terms.

-1/6x+4+1/3x=x+4

Multiply both sides -1/6x+1/3x=x

collect like terms.

-x+2x=6x

move the variable from right to left.

x=6x

collect like terms

x-6x=0

Divide both sides

-5x=0

x=0

7 0
3 years ago
kurt used yhe rule add 4, subtract 1 to generate a pattern.the first term in his pattern is 5.write a number that could be in ku
marishachu [46]

Answer:

Kurt pattern is:

5,8,11,14,17 and so on

Step-by-step explanation:

we are given that:

kurt used the rule add 4, subtract 1 to generate a pattern.

The first term in his pattern is 5.

We have to write a number that could be in kurts pattern.

Now, he adds 4 and subtract 1 means the second term will be

5+4-1=8

Third term will be, 8+4-1=11

Fourth term will be 11+4-1=14

Fifth term will be 14+4-1=17

Hence, Kurt pattern is:

5,8,11,14,17 and so on

7 0
3 years ago
Read 2 more answers
Mrs Amnda du Toit purchase the lounge
Masja [62]

Answer:

This isn't even a language

Step-by-step explanation:

6 0
2 years ago
Which perfect square equation represents x^2+4x+1=0 by completing the square?
natali 33 [55]
First thing to do is to move the constant over to the other side of the equals sign.  Then we will complete the square on the x terms.  We will take half the linear term, square it, then add it to both sides.  Our linear term is 4.  Half of 4 is 2, and 2 squared is 4. x^2+4x+4=-1+4.  In the process of completing the square we have created a perfect square binomial on the left which is (x+2)^2=3.  A is our answer.
7 0
3 years ago
Find the quotient. -1/5 divided by 1 2/8
Serjik [45]

Answer:

-4/25

Step-by-step explanation:

-1/5 ÷ 1 2/8

-1/5 ÷ 10/8

-1/5 ÷ 5/4

-1/5 * 4/5

-4/25

Best of Luck!

5 0
3 years ago
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