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KatRina [158]
3 years ago
10

Assessment timer and count

Mathematics
1 answer:
Tanya [424]3 years ago
7 0

Answer: y=300⋅2.03x

Step-by-step explanation:

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Helpppp me plz i need help​
daser333 [38]

Answer:

The answer is D

Step-by-step explanation:

I learned this in school

6 0
3 years ago
Suppose that $1,000 is deposited into an account that yields 0.85% interest, compounded annually.
andrey2020 [161]
<h3>Answer:  1034.44 dollars</h3>

=====================================

Work Shown:

A = P*(1+r/n)^(n*t)

A = 1000*(1+0.0085/1)^(1*4)

A = 1034.43596172007

A = 1034.44

---------------------

Notes:

  • P = 1000 is the deposit or principal
  • r = 0.0085 is the decimal form of the annual interest rate of 0.85%; we can say 0.85% = 0.85/100 = 0.0085
  • n = 1 represents how many times per year we're compounding the money (ie annually)
  • t = 4 = number of years
  • The result of 1034.44 dollars is only possible if you do not withdraw any of the money in the four year time period.
4 0
2 years ago
What fraction of an inch is 1 cm
GarryVolchara [31]

Answer:

The answer is .393.  Hope this helps.

3 0
2 years ago
Read 2 more answers
Jenny drove 303 miles using 15 gallons of gas. At this rate, how many miles would she drive using 16 gallons of gas?
Alecsey [184]

Answer:

303/15 is 20.2

20.2*16 is 323.2

so 323.2 miles

8 0
2 years ago
Read 2 more answers
among a group of students 50 played cricket 50 played hockey and 40 played volleyball. 15 played both cricket and hockey 20 play
kondaur [170]

Answer:

Cricket only= 30

Volleyball only = 15

Hockey only = 25

Explanation:

Number of students that play cricket= n(C)

Number of students that play hockey= n(H)

Number of students that play volleyball = n(V)

From the question, we have that;

n(C) = 50, n(H) = 50, n(V) = 40

Number of students that play cricket and hockey= n(C∩H)

Number of students that play hockey and volleyball= n(H∩V)

Number of students that play cricket and volleyball = n(C∩V)

Number of students that play all three games= n(C∩H∩V)

From the question; we have,

n(C∩H) = 15

n(H∩V) = 20

n(C∩V) = 15

n(C∩H∩V) = 10

Therefore, number of students that play at least one game

n(CᴜHᴜV) = n(C) + n(H) + n(V) – n(C∩H) – n(H∩V) – n(C∩V) + n(C∩H∩V)

= 50 + 50 + 40 – 15 – 20 – 15 + 10

Thus, total number of students n(U)= 100.

Note;n(U)= the universal set

Let a = number of people who played cricket and volleyball only.

Let b = number of people who played cricket and hockey only.

Let c = number of people who played hockey and volleyball only.

Let d = number of people who played all three games.

This implies that,

d = n (CnHnV) = 10

n(CnV) = a + d = 15

n(CnH) = b + d = 15

n(HnV) = c + d = 20

Hence,

a = 15 – 10 = 5

b = 15 – 10 = 5

c = 20 – 10 = 10

Therefore;

For number of students that play cricket only;

n(C) – [a + b + d] = 50 – (5 + 5 + 10) = 30

For number of students that play hockey only

n(H) – [b + c + d] = 50 – ( 5 + 10 + 10) = 25

For number of students that play volleyball only

n(V) – [a + c + d] = 40 – (10 + 5 + 10) = 15

3 0
3 years ago
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