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Answer:
4. height: 5√3 cm; area: 25√3 cm²
5. 30√2 ft ≈ 42.43 ft
Step-by-step explanation:
4. The height of an equilateral triangle is (√3)/2 times the side length, so is ...
height = (√3)/2 × (10 cm) = 5√3 cm
The area is given by the formula ...
A = 1/2bh
A = 1/2(10 cm)(5√3 cm) = 25√3 cm²
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5. The diagonal of a square is √2 times the side length, so the distance from 3rd to 1st base is ...
(30 ft)√2 ≈ 42.43 ft
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The length of the diagonal of a square is something you should be familiar with. If you're not, you can figure the distance using the Pythagorean theorem.
d = √(30² +30²) = √1800 ≈ 42.43 . . . feet
Answer:
2nd option
Step-by-step explanation:
A difference of squares has the general form
a² - b²
where the terms on either side of the subtraction ( the difference ) are both perfect squares.
The only one fitting this description is
16a² - 4y²
= (4a)² - (2y)² ← difference of squares
Answer:
Average rate of change is <u>0.80.</u>
Step-by-step explanation:
Given:
The two points given are (5, 6) and (15, 14).
Average rate of change is the ratio of the overall change in 'y' and overall change in 'x'. If the overall change in 'y' is positive with 'x', then average rate of change is also positive and vice-versa.
The average rate of change for two points 
is given as:
Plug in 
and solve for 'R'. This gives,
Therefore, the average rate of change for the points (5, 6) and (15, 14) is 0.80.
Answer:
a. Inscribed angle = <WXY
b. Minor arc = arc(XY)
c. VWX
d. m(VWX) = 180°
e. m<VUW = 110°
Step-by-step explanation:
a. The angle, <WXY has its vertex on the circumference of the circle. Therefore, it can be referred to as an inscribed angle of the circle with center U.
Inscribed angle = <WXY
b. Arc(XY) is a minor arc because it is smaller than half of circle with center U.
Minor arc = arc(XY)
c. A semicircle is half of a full rotation for a circle. From the diagram, a semicircle is VWX
d. m(VWX) = Half the rotation of a full circle = 180°
e. m<VUW = arc(VW) (measure of central angle = measure of arc)
m<VUW = 110° (Substitution)
I feel like I’m seeing the same question a lot
