x = first integer
x+1 = integer right after x
For example, if x = 10, then the next one after that is x+1 = 10+1 = 11. So 10 and 11 are consecutive integers (one follows right after the other)
The sum of those two integers x and x+1 add to x+x+1 = 2x+1
This sum is no more than 209, therefore,
![2x+1 \le 209](https://tex.z-dn.net/?f=2x%2B1%20%5Cle%20209)
![2x+1-1 \le 209-1](https://tex.z-dn.net/?f=2x%2B1-1%20%5Cle%20209-1)
![2x \le 208](https://tex.z-dn.net/?f=2x%20%5Cle%20208)
![\frac{2x}{2} \le \frac{208}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%7D%7B2%7D%20%5Cle%20%5Cfrac%7B208%7D%7B2%7D)
![x \le 104](https://tex.z-dn.net/?f=x%20%5Cle%20104)
Therefore the largest x can be is 104
If x = 104, then x+1 = 104+1 = 105
<h3>Final Answer: 105</h3>
Note how 104+105 = 209, which helps confirm the answer
To find the answer to Part A on the second part, you simply multiply 4 by 2 and you get 8. Then, you multiply 6 by 2 and you get 12. Then your answer is 8 by 12.
Part B: The area of the enlarged area of the garden is enlarged by 2 times the original lengths.
Equation:
37 = 12x
37 / 12 = x
3.0833... = x
Hope it helped,
Happy homework/ study/ exam!