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trasher [3.6K]
3 years ago
12

Solving right triangles geometry help please

Mathematics
1 answer:
Alex73 [517]3 years ago
3 0

Answer:

(13) The third side is 14 cm

(13) The third side is 16.1 cm

Step-by-step explanation:

Given

(13) & (14)

Required

Solve

(13): Let length AB = x.

Using Pythagoras theorem.

x^2 = 12^2 + 9^2

x^2 = 144 + 81

x^2 = 225

Take positive square root of both sides

x = \sqrt{225

x = 15

(14): Let length DE = x.

Using Pythagoras theorem.

x^2 = 8^2 + 14^2

x^2 = 64 + 196

x^2 = 260

Take positive square root of both sides

x = \sqrt{260

x = 16.1 ---approximated

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Henry has collected data to find that the typing speeds for the students in a typing class has a normal distribution. What is th
Mekhanik [1.2K]

Answer: 0.8413

Step-by-step explanation:

Given : Henry has collected data to find that the typing speeds for the students in a typing class has a normal distribution.

Mean : \mu=47

Standard deviation : \sigma= 4

Let x be the random variable that represents the typing speeds for the students.

The z-score :-

z=\dfrac{x-\mu}{\sigma}

For x= 51

z=\dfrac{51-47}{4}=1

Using the standard normal distribution table ,the probability that a randomly selected student has a typing speed of less than 51 words per minute :-

P(x

Hence, the probability that a randomly selected student has a typing speed of less than 51 words per minute = 0.8413

8 0
3 years ago
Explain what is wrong with each of the following randomization procedures, and describe how you would do the randomization corre
zlopas [31]

Answer:

Kindly check explanation

Step-by-step explanation:

A.)

The problem with the here is that we might have introduced bias into our sample by failing to randomize the assignment of gender. By pacing the male gender in the treatment group and females into the control group, this might spring up a spurious association in our experiment as a result of a possible confounding variable, gender. Therefore, assignment of subject shouldn't be on the basis of gender.

2.)

Using a coin toss in placing subjects into groups will give a good random assignment, however, since only ten subjects are available and of which 5 will be placed into each group, there is no certainty that there will be equal number of heads and tails during the 10 flips. Alternatively, a random selection of the name of the 10 subjects could be chosen from a raffle.

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Each batch of rat might be homogenous and hence will affect our experiment and definitely our conclusion. It would be best to assign rats from each batch to all treatment groups in other to obtain a good random design

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3 years ago
Here are the percents of the popular
kvv77 [185]

Answer: 57.4

Step-by-step explanation:

First order the numbers from the smallest to the largest:

49.6, 55.1, 57.4, 49.7, 61.1, 43.4,  60.7, 50.1, 50.7, 58.8, 53.9, 43.2,  49.2, 47.9, 51.2

to:

43.2, 43.4, 47.9, 49.2, 49.6, 49.7, 50.1, 50.7, 51.2, 53.9, 55.1, 57.4, 58.8, 60.7, 61.1.

The position of third quartile is:

= (N + 1) * 3/4

= (15 + 1) * 3/4

= 12th position

That number is:

= 57.4

8 0
3 years ago
Joaquin bought a bookcase on sale for $120, which was two-thirds of the original price. What was the original price of the bookc
weqwewe [10]
180
Because 120 divided by 2 is 60.
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ANSWER FAST PLZ 65 POINTS!!!!!!!!!!!!!!!!!!
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Using the information in the problem you have:

A= PI x 15^2

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8 0
3 years ago
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