Question

the width of a rectangle is 8 feet and the diagnal length of the rectangle is 13 feet which measurement is closest to the length of this rectangle in feet

Answer 1

Answer:

Well the whole answer is 10.246950 smth smth but I don’t have the multiple choices so your gonna have to round yourself

Step-by-step explanation:

Okay so you have a weigh of 8 and a diagonal of 13.

If you look, theres a triangle there. One side has 8 and the diagonal that was cut forms a 13. So we have a leg and a hypotnuse. To find the other leg (length) just follow the Pythagorean theroum and solve for b or a.

Pythagorean theroum: a^2+b^2=c^2

Now subsitute c for 13 since its the hypotnuse and a or b as 8 but only one.

In this case I’m substituting a for 8.

8^2+b^2=13^2

Solve the squares

64+b^2= 169

Isolate the b

b^2=105

Now square root 105

√105 will give the answer above on a normal calculator but if you have to round, I don’t know what place but you can round.